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ch4aika [34]
4 years ago
11

In the first quadrant you start at 3,6 and move 4 units right and 2 units up what point would you end up on

Mathematics
2 answers:
Taya2010 [7]4 years ago
8 0

Answer:

(7,8)

Step-by-step explanation:

(x-axis) 4+3 (x-axis)=7

(y-axis) 6+2 (y-axis)=8

cupoosta [38]4 years ago
6 0

Answer:

(7,8)

Step-by-step explanation:

By moving 4 units right the x increases: 3+4=7. When moving 2 units up the y increases: 6+2=8.

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- Inessa ran 3 laps in 10 minutes. How long
Anni [7]

Answer: 16 minutes and 40 seconds

Step-by-step explanation:

1.) Divide 10 minutes by 3 laps in order to find out how long it takes her to run a single lap. (it ends up being 3 minutes and 20 seconds per lap)

2.) Multiply this number by 5, you get 16 minutes and 40 seconds.

NOTE: remember that you’re using intervals of 60 (seconds in a minute) rather than intervals of 100.

8 0
3 years ago
What is the quotient of 2 1/4 and 5/8?
Akimi4 [234]

Answer:

2

Step-by-step explanation:

3 0
3 years ago
A rectangle is transformed according to the rule r0, 90º. the image of the rectangle has vertices located at r'(–4, 4), s'(–4, 1
Korvikt [17]

Answer:

Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

Counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Step-by-step explanation:

Given  : rectangle has vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4)

To find :  transformed according to the rule 90º , what is the location of q?

Solution : we have given that

vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4).

By the rule of 90º rotation clock wise rule : (x ,y ) →→ ( y , -x )

90º rotation counter clock wise rule : (x ,y ) →→ ( -y , x ).

Then   Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Therefore, Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

4 0
3 years ago
Read 2 more answers
(csc x - 1) (csc x + 1)
victus00 [196]
<h2>Explanation:</h2>

Here we have the following expression:

(csc x - 1) (csc x + 1)

So we need to extend this. Remember that the difference of squares tells us:

(a-b)(a+b)=a^2-b^2

So here:

a=cscx \\ \\ b=1

Thus:

(csc x - 1) (csc x + 1)=csc^2x-1 \\ \\ \\ But: \\ \\ cscx=\frac{1}{sinx} \\ \\ \\ Then: \\ \\ csc^2x-1=\frac{1}{sin^2x}-1=\frac{1-sin^2x}{sin^2x}=\frac{cos^2x}{sin^2x}=cot^2x \\ \\ \\ Finally: \\ \\ \boxed{(csc x - 1) (csc x + 1)=cot^2x}

4 0
3 years ago
Geomtry plz help 15 points
VladimirAG [237]

Answer:

m∠E=57°

Step-by-step explanation:

∠FDE=∠FED=(4x+1)° (base angles of isos triangle)

2(4x+1)+(5x-4)=180 (angle sum of triangle)

    8x+2+5x-4=180

             13x-2=180

                 13x=180+2

                       =182

                     x=182÷13

                       =14

Hence, m∠E = (4x+1)°

                     = [4(14)+1]°

                     = (56+1)°

                     = 57°

5 0
2 years ago
Read 2 more answers
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