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V125BC [204]
3 years ago
9

A rectangle is transformed according to the rule r0, 90º. the image of the rectangle has vertices located at r'(–4, 4), s'(–4, 1

), p'(–3, 1), and q'(–3, 4). what is the location of q?
Mathematics
2 answers:
8_murik_8 [283]3 years ago
6 0
PRETTY sure the answer you're looking for is:
D. (4, 3)
Let me know if I'm right!
Korvikt [17]3 years ago
4 0

Answer:

Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

Counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Step-by-step explanation:

Given  : rectangle has vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4)

To find :  transformed according to the rule 90º , what is the location of q?

Solution : we have given that

vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4).

By the rule of 90º rotation clock wise rule : (x ,y ) →→ ( y , -x )

90º rotation counter clock wise rule : (x ,y ) →→ ( -y , x ).

Then   Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Therefore, Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

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4 0
3 years ago
The height of a triangle is 8 cm more than the base. If the area is 24 cm2, find the height and base of the triangle.
Elden [556K]

Answer:

height = 12 cm

base length = 4 cm

Step-by-step explanation:

area of a triangle

base length × height / 2

x = height

y = base length

x = y + 8

24 = y × (y + 8) / 2

48 = y × (y + 8) = y² + 8y

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solution

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a = 1

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but a negative base length did not make any sense, so only y = 4 remains.

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5 0
3 years ago
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Fiesta28 [93]
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8 0
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