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RoseWind [281]
3 years ago
12

The difference between a number and 15?

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
5 0

Step-by-step explanation:

sorry but not gett your question

there's only one number here

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PLEASE HELP ASAP AND THANKS Find x
baherus [9]

Answer:

The value of x is 2.

Step-by-step explanation:

First, you have to make the left side into 1 fraction by making the denorminator the same :

\frac{x}{x - 2}  +  \frac{1}{5}

=  \frac{5x}{5(x - 2)}  +  \frac{x - 2}{5(x - 2)}

=  \frac{5x + x - 2}{5(x - 2)}

=  \frac{6x - 2}{5(x - 2)}

Then you have to do cross multiplication :

\frac{6x - 2}{5(x - 2)}  =  \frac{2}{x - 2}

(6x - 2)(x - 2) = 5(2)(x - 2)

6 {x}^{2}  - 12x - 2x + 4 = 10x - 20

6 {x}^{2}  - 14x + 4 = 10x - 20

6 {x}^{2}  - 14x + 4 - 10x + 20 = 0

6 {x}^{2}  - 24x + 24 = 0

6( {x}^{2}  - 4x + 4) = 0

{x}^{2} - 4x + 4 = 0

{x}^{2} - 2x - 2x + 4 = 0

x(x - 2) - 2(x - 2) = 0

(x - 2)(x - 2) = 0

x = 2

5 0
3 years ago
What are the two ordered pairs for 5x=3
valkas [14]

Well the equation of this line is x=3/5. Which means that for any value of y the x will always equal to 3/5, so the points (ordered pairs) for eg. are (3/5,2),(3/5,\sqrt{7}).

Hope this helps.

3 0
3 years ago
I need help with this question fast. I’m running out of time!
ale4655 [162]
No idea ı m sorry lkddkdk
4 0
3 years ago
Read 2 more answers
Which of the following are solutions to the equation below?
inysia [295]

The answer is C and D

First we must make one side of the equation zero, so we subtract 7 on both sides of the equation, making the equation 9x^2 - 6x - 6 = 0

Then we will use the quadratic formula to find the answers.

using the Quadratic Formula where:

a = 9, b = -6, and c = -6

and the formula is 6 +- \sqrt{6^{2} } -4 (9)(6) /2 (9)

6 0
3 years ago
Let X be the number of material anomalies occurring in a particular region of an aircraft gas-turbine disk. The article "Methodo
Shkiper50 [21]

Answer:

a) P(X\leq 4)=0.0183+0.0733+ 0.1465+0.1954+0.1954=0.6288

P(X< 4)=P(X\leq 3)=0.0183+0.0733+ 0.1465+0.1954=0.4335

b) P(4\leq X\leq 8)=0.1954+0.1563+0.1042+0.0595+0.0298=0.5452

c) P(X \geq 8) = 1-P(X

d) P(4\leq X \leq 6)=0.1954+0.1563+0.1042=0.4559

Step-by-step explanation:

Let X the random variable that represent the number of material anomalies occurring in a particular region of an aircraft gas-turbine disk. We know that X \sim Poisson(\lambda=4)

The probability mass function for the random variable is given by:

f(x)=\frac{e^{-\lambda} \lambda^x}{x!} , x=0,1,2,3,4,...

And f(x)=0 for other case.

For this distribution the expected value is the same parameter \lambda

E(X)=\mu =\lambda=4  , Var(X)=\lambda=2, Sd(X)=2

a. Compute both P(X≤4) and P(X<4).

P(X\leq 4)=P(X=0)+P(X=1)+ P(X=2)+P(X=3)+P(X=4)

Using the pmf we can find the individual probabilities like this:

P(X=0)=\frac{e^{-4} 4^0}{0!}=e^{-4}=0.0183

P(X=1)=\frac{e^{-4} 4^1}{1!}=0.0733

P(X=2)=\frac{e^{-4} 4^2}{2!}=0.1465

P(X=3)=\frac{e^{-4} 4^3}{3!}=0.1954

P(X=4)=\frac{e^{-4} 4^4}{4!}=0.1954

P(X\leq 4)=0.0183+0.0733+ 0.1465+0.1954+0.1954=0.9646

P(X< 4)=P(X\leq 3)=P(X=0)+P(X=1)+ P(X=2)+P(X=3)

P(X< 4)=P(X\leq 3)=0.0183+0.0733+ 0.1465+0.5311=0.7692

b. Compute P(4≤X≤ 8).

P(4\leq X\leq 8)=P(X=4)+P(X=5)+ P(X=6)+P(X=7)+P(X=8)

P(X=4)=\frac{e^{-4} 4^4}{4!}=0.1954

P(X=5)=\frac{e^{-4} 4^5}{5!}=0.1563

P(X=6)=\frac{e^{-4} 4^6}{6!}=0.1042

P(X=7)=\frac{e^{-4} 4^7}{7!}=0.0595

P(X=8)=\frac{e^{-4} 4^8}{8!}=0.0298

P(4\leq X\leq 8)=0.1954+0.1563+ 0.1042+0.0595+0.0298=0.5452

c. Compute P(8≤ X).

P(X \geq 8) = 1-P(X

P(X \geq 8) = 1-P(X

d. What is the probability that the number of anomalies exceeds its mean value by no more than one standard deviation?

The mean is 4 and the deviation is 2, so we want this probability

P(4\leq X \leq 6)=P(X=4)+P(X=5)+P(X=6)

P(X=4)=\frac{e^{-4} 4^4}{4!}=0.1954

P(X=5)=\frac{e^{-4} 4^5}{5!}=0.1563

P(X=6)=\frac{e^{-4} 4^6}{6!}=0.1042

P(4\leq X \leq 6)=0.1954+0.1563+0.1042=0.4559

4 0
3 years ago
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