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3 years ago

What is the volume of a container measured in liquid units

Mathematics

2 answers:

Alisiya [41]3 years ago

7 0

Answer:

A Liter

Step-by-step explanation:

saveliy_v [14]3 years ago

3 0

Step-by-step explanation:

liters

The capacity of a container is the volume of a container measured in liquid units. Cups, pints, quarts, and gallons are customary units of measurement. Two metric units of capacity are milliliters and liters. A milliliter is equal to about 20 drops from an eyedropper.

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PLEASE HELP :( ASAP

kenny6666 [7]

Answer:

A. 272 cm^2

Step-by-step explanation:

The area of the rectangle is 17cm * 7cm = 119 cm^2

The area of the right triangle is (25-7) * 17cm * 1/2 = 153cm^2

<em>Answer: 119+153 = 272 cm^2</em>

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2 years ago

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(09.02 MC) Which of the following tables shows the correct steps to transform x2 + 10x + 24 = 0 into the form (x − p)2 = q? [p a

Vladimir79 [104]

Answer: step 2

Step-by-step explanation:

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3 years ago

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For a certain experiment, if we expect to get an apple 8 times in 200 trials, what is the theoretical probability of getting an

Maurinko [17]

The answer is C

If you divide 8 by 200 it becomes 0.04 which is 4/100 in fraction form. If you simplify it then become 1/25.

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3 years ago

A store is having a 20% off sale on all merchandise If Mai buys one item and save $13 what was the original price of her purchas

katrin [286]

Answer:

Step-by-step explanation:

20% off...and she saves $13

so 20% of what number is 13

0.20x = 13

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x = 65 <== original price

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3 years ago

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A recent study found that the average length of caterpillars was 2.8 centimeters with a

pogonyaev

Using the normal distribution, it is found that there is a 0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In this problem, the mean and the standard deviation are given, respectively, by:

$\mu = 2.8, \sigma = 0.7$ .

The probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters is <u>one subtracted by the p-value of Z when X = 4</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{4 - 2.8}{0.7}$

Z = 1.71

Z = 1.71 has a p-value of 0.9564.

1 - 0.9564 = 0.0436.

0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

More can be learned about the normal distribution at brainly.com/question/24663213

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2 years ago