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svetoff [14.1K]
3 years ago
11

(10 points) help!!! Pls

Mathematics
1 answer:
Fofino [41]3 years ago
8 0

Answer:

There's 3 answers: the third, fourth, and the sixth one. 1  2  3

                                                                                           4  5  6

Step-by-step explanation:

The expression in the question gets simplified to p-6, and so does the third one, fourth one is just itself, and the sixth one also simplifies to p-6.

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Simplify. –22 + (–5) ∙ 6 A. –162 B. –52 C. 8 D. 162
Fofino [41]
The correct answer is B
7 0
4 years ago
Maths Trigonometry Question<br> 100 points up for grabs!<br> Will give brainliest to whoever answers
Gekata [30.6K]

Answer:

14) 21.136505024965 m

15) 43.076759215619 km

Step-by-step explanation:

14)

let h be the height of the lighthouse:

tan(41.3) = 18.7/h

Then

h = 18.7÷tan(41.5)

  = 21.136505024965 m

………………………………………

15)

90-71.4 =18.6

Let s be the distance that the plane flew

towards the south:

tan(90 - 71.4) = s/128

Then

tan(18.6) = s/128

Then

s = tan(18.6)×128

  = 43.076759215619 km

5 0
2 years ago
Read 2 more answers
What’s the equation you’re suppose to make?
ioda

Answer:

To begin with we know that a line must have an angle measure of 180, and those two angles in your photo are supplementary angles. Based on this you get this equation: 8x+6+118=180, the answer of that is 8x=56 simplify it to get x=7

5 0
3 years ago
The vector wequalsaiplusbj is perpendicular to the line axplusbyequalsc and parallel to the line bxminusayequalsc. It is also tr
Likurg_2 [28]

Answer:

\theta=45^{\circ}

Step-by-step explanation:

We are given that the equation of lines

x+\sqrt 3y=1

(1-\sqrt 3)x+(1+\sqrt 3)y=8

According to question

The vector perpendicular to the lines is given by

i+\sqrt 3j and (1-\sqrt 3)i+(1+\sqrt 3)j

Therefore, the  angle between two vectors is given by

cos\theta=\frac{a_1a_2+b_1b_2}{\sqrt{a^2_1+b^2_1}\sqrt{a^2_2+b^2_2}}

Using the formula

cos\theta=\frac{1(1-\sqrt 3)+\sqrt 3(1+\sqrt 3)}{2\times 2\sqrt 2}

cos\theta=\frac{1-\sqrt 3+\sqrt 3+3}{4\sqrt 2}=\frac{1}{\sqrt 2}

cos\theta=cos 45^{\circ}

\theta=45^{\circ}

Hence, the acute angle between the lines is given by

\theta=45^{\circ}

3 0
3 years ago
The first side of a triangle is 4m shorter than the second side. The third side 3 times as long as the first side. The perimeter
viktelen [127]

Answer:

1st side= 4m

2nd side= 8m

3rd side= 12m

Step-by-step explanation:

Let the first, second and third side of the triangle be a, b and c meters respectively.

a= b -4 -----(1)

c= 3a -----(2)

Perimeter of triangle

= a +b +c

= 24

a +b +c= 24 -----(3)

From (1): b= a +4 -----(4)

Subst. (2) and (4) into (3):

a +(a +4) +3a= 24

3a +a +a +4= 24

5a +4= 24

5a= 24 -4

5a= 20

Divide both sides by 5:

a= 20 ÷5

a= 4

Substitute a= 4 into (4):

b= 4 +4

b= 8

Substitute a= 4 into (2):

c= 3(4)

c= 12

Thus, the lengths of the first, second, and third side of the triangle are 4m, 8m and 12m respectively.

4 0
3 years ago
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