Answer:
log base 3a= -0.631.log a/3 base 3
Now, -log m= log 1/m
hence,
log base 3a= 0.631.log 3/a base 3
log base 3a/log 3/a base 3 =0.631
log base 3 ( a.3/a) =.631 since, log m/logn =log n(m)
log base 3 3=0.631
Hence, answer is log base 3 3=0.631
Explanation:
Please check the answer section.
Answer:
denial-of-service attack (DoS attack) and distributed denial-of-service attack (DDoS attack)
Explanation:
Denial-of-service attack -
It is a type of cyber attack , where the hacker can create a machine or any network resource , which is capable to disrupt the server of the host , with the help of the internet , is referred to as the denial of service attack .
The task is accomplished with by flooding the host with many superfluous requests , which can overload the system .
In case of the distributed denial-of-service attack , the flooding is done by many different sources .
Hence , from the given scenario of the question ,
The correct answer is denial-of-service attack (DoS attack) and distributed denial-of-service attack (DDoS attack) .
Answer:
Following is the program in C++ Language
#include <iostream> // header file
using namespace std; // namespace std
int main() // main method
{
int n; // variable declaration
cout<<" Please enter the number :";
cin>>n; // Read the number
if(n>0) // check the condition when number is positive
{
cout<<n<<endl<<"The number is Positive"; // Display number
}
else if(n<0) // check the condition when number is Negative
{
cout<<n<<endl<<"The number is Negative";// Display number
}
else // check the condition when number is Zero
{
cout<<n<<endl<<"The number is Zero";// Display number
}
return 0;
}
Output:
Please enter the number:
64
The number is Positive
Explanation:
Following are the description of the program
- Declared a variable "n" of int type.
- Read the value of "n" by user.
- Check the condition of positive number by using if block statement .If n>0 it print the number is positive.
- Check the condition of negative number by using else if block statement If n<0 it print the number is negative.
- Finally if both the above condition is fail it print the message " The number is Zero"
Answer:
The answer to this question is "nested".
Explanation:
The answer to this question is nested because, In programming languages, there is a concept of nested if-else statement. In nested if-else statement placing if statement inside another IF Statement that is known as nested If in C Programming.
Example of nested if can be given as
#include <stdio.h>
int main()
{
int a,b,c;
printf("Enter 3 number\n");
scanf("%d",&a);
scanf("%d",&b);
scanf("%d",&c);
if(a>b)
{
if(a>c)
{
printf("A is greater: %d",a);
}
}
else
{
if(b>c)
{
printf("B is greater: %d",b);
}
else
{
printf("C is greater: %d",c);
}
}
return 0;
}
output:
Enter 3 number
4
7
9
c is greater: 9
