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Sergio [31]
3 years ago
10

Write a program that prompts the user to input a number. The program should then output the number and a message saying whether

the number is positive, negative, or zero.
Computers and Technology
1 answer:
Gala2k [10]3 years ago
7 0

Answer:

Following is the program in C++ Language

#include <iostream> // header file

using namespace std; // namespace std

int main() // main method

{

   int n;  // variable declaration

   cout<<" Please enter the number :";

   cin>>n; // Read the number

   if(n>0) // check the condition when number is positive

   {

cout<<n<<endl<<"The number is Positive"; // Display number

   }

  else if(n<0) // check the condition when number is Negative

  {

cout<<n<<endl<<"The number is Negative";// Display number

  }

  else // check the condition when number is Zero

  {

cout<<n<<endl<<"The number is Zero";// Display number

  }

   return 0;

  }

Output:

Please enter the number:

64

The number is Positive

Explanation:

Following are the description of the program

  • Declared a variable "n" of int type.
  • Read the value of "n" by user.
  • Check the condition of positive number by using if block statement .If n>0 it print the number is positive.
  • Check the condition of negative number by using else if block statement If n<0 it print the number is negative.
  • Finally if both the above condition is fail it print the message " The number is Zero"

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A profit of ₹ 1581 is to be divided amongst three partner P,Q and R in ratio 1/3:1/2:1/5.theshareof R will be?​
Burka [1]

Answer:

R's share = 306

Explanation:

Sum of ratio = 1/3 + 1/2 + 1/5

LCM = 30

Sum of ratio = (10 + 15 + 6) / 30 = 31 /30

Profit to be shared = 1581

P = 1/3 ; Q = 1/2 ; R = 1/5

Share of R :

(Total profit / sum of ratio) * R ratio

[1581 / (31/30)] * 1/5

(1581 / 1 * 30/31) * 1/5

51 * 30 * 1/5

51 * 6 = 306

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3 years ago
Write a C program to implement a command called ​displaycontent ​that takes a (text) file name as argument and display its conte
Zanzabum

Answer:

/*

Student: Hugo Meza

Date: February 15, 2019

Description: This program mimic the cat command from Linux. Checks whether the source file

has the right permissions, and then writes in the console its content.

*/

#include <stdio.h>

#include <fcntl.h>

#include <unistd.h>

#include <errno.h>

int hasPermission(char *filepath){

int returnval;

// Check file existence

returnval = access (filepath, F_OK);

if(errno == ENOENT){

printf ("%s does not exist\n", filepath);

return 0;

}

else if (errno == EACCES){

printf ("%s is not accessible\n", filepath);

return 0;

}

// Check read access

returnval = access (filepath, R_OK);

if(errno == ENOENT){

printf ("%s does not have read access\n", filepath);

return 0;

}

else if (errno == EACCES){

printf ("%s is not accessible\n",filepath);

return 0;

}

// Check write access

returnval = access (filepath, W_OK);

if(errno == ENOENT){

printf ("%s does not have read access\n", filepath);

return 0;

}

else if (errno == EACCES){

printf ("%s is not accessible\n",filepath);

return 0;

}

return 1;

}

int main(int argc, char* argv[]){

if(!argv[1]){

printf("Error. Specify file to open\n");

return 0;

}

int fd;

char *fp = argv[1], content[fd];

if(hasPermission(fp) == 0)

return 1;

fd = open(fp, O_RDONLY);

int bytes = read(fd,content,sizeof(content)-1);

write(1, content, bytes);

close(fd);

return 0;

}

Explanation:

7 0
3 years ago
71 81 77 15 63 96 36 51 77 18 17
sp2606 [1]

Answer:

Following are the solution to this question:

Explanation:

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It splits down the list in more than one version frequently till every sublist becomes based on a single element and fuses it to offer an ordered array. The merge type works according. It has O(n*log n) complexity.

Please find the attachment file of the sorting.

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