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lys-0071 [83]
3 years ago
8

WXZY is a quadrilateral with W located at (-5, 2) and X is located at (3, 0). What must be the slope of ZY in order for WXYZ to

be a parallelogram?

Mathematics
1 answer:
Verdich [7]3 years ago
3 0

Answer:  The answer is -\dfrac{1}{4}.


Step-by-step explanation:  Given that WXZY is a quadrilateral with W located at (-5, 2) and X is located at (3, 0). We need to find the slope of ZY for which the quadrilateral WXZY is a parallelogram.

We know that the opposite sides of a parallelogram are parallel to each other. So, in the attached figure, we must have WX parallel to ZY. And for that, slope of WX = slope of ZY.

Slope of WX is given by

m=\dfrac{0-2}{3-(-5)}=\dfrac{-2}{8}=-\dfrac{1}{4}.

Thus, the slope of ZY must be -\dfrac{1}{2}.



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