Answer:
Step-by-step explanation:
ignore the "at the instant the man is 30 feet away" part, set it as X and the man's shadow as Y.
Similar triangles so we can do .
Solve for it we get 44y = 6x
Differentiate relative to time t, we get 44y' = 6x'.
change in x (x') is equal to 5. And we get the answer y' = .
the ft/sec is the rate of which the length of the shadow is changing. add 5 to it for the rate of the tip of his shadow moving away from the tower.
<ADC = <BAD = 115
hope it helps
Answer:
a)6
b)v^2-u^2/2a
Step-by-step explanation:
a)Given that,
u=12
a= -6
s=9
We know that,
v^2=u^2+2as
or, v^2=(12)^2+2×(-6)×9
or,v^2=144-108
or,v^2=36
or, v=√36
∴v=6
(Ans)
b)If ,v^2=u^2+2as
then, u^2+2as=v^2
or,2as=v^2-u^2
or, s=v^2-u^2/2a
∴s=v^2-u^2/2a
Hope ya find it helpful.. Thanks a lot...
See the attached figure
we know that
[<span>the area of the trapezoid]=[area rectangle]+2*[area triangle]
</span>[the area of the trapezoid]=[14*12]+2*[12*2/2]=192 in²
the answer is 192 in²