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3 years ago

What is the sum of 2/10 and 20/100

Mathematics

2 answers:

yawa3891 [41]3 years ago

7 0

2 / 10 = 20 / 100.

So 2 /10 + 2 / 10 = 4 / 10.

Simplify that to 2 / 5.

zaharov [31]3 years ago

5 0

The awnser to your question would be 40/100 because sense you have to find the least common denominator (LCM) all you have to do is do 10*10 and 2*10 which equals 20/100 and THEN out do 20/100 plus 20/100 which equals 40/100.

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For a sample size of 20 players, 68% of the sample means fall within 19.32 and 20.98

<h3>What is a sample size?</h3>

The sample size is a term used in market research for defining the number of subjects included in a sample size. By sample size, we understand a group of subjects that are selected from the general population and is considered a representative of the real population for that specific study.

Empirical rule states that for a normal distribution, 68% of the values are within one standard deviation from the mean, 95% of the values are within two standard deviation from the mean and 99.7% of the values are within three standard deviation from the mean.

For a population mean of 20.15 and a standard deviation of 3.7

68% are within μ ± σ/√n,

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68% = 20.15 ± 3.7/√20 = (19.32, 20.98)

For a sample size of 20 players, 68% of the sample means fall within 19.32 and 20.98.

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Vladimir [108]

Answer:

The value of t test statistics is 5.9028.

We conclude that the true mean is greater than 10 at the .01 level of significance.

Step-by-step explanation:

We are given that a firm issued a guideline that transmissions of 10 pages or more should be sent by 2-day mail instead.

The firm examined 35 randomly chosen fax transmissions during the next year, yielding a sample mean of 14.44 with a standard deviation of 4.45 pages.

<em />

<em>Let </em> $\mu$ <em> = true mean transmission of pages.</em>

So, Null Hypothesis, $H_0$ : $\mu$ $\leq$ 10 pages {means that the true mean is smaller than or equal to 10}

Alternate Hypothesis, $H_A$ : $\mu$ > 10 pages {means that the true mean is greater than 10}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

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So, <u><em>test statistics</em></u> = $\frac{14.44-10}{\frac{4.45}{\sqrt{35} } }$ ~ $t_3_4$

= 5.9028

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Now, at 0.01 significance level the z table gives critical values of 2.441 at 34 degree of freedom for right-tailed test.

<em>Since our test statistics is more than the critical values of z as 5.9028 > 2.441, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><em><u>we reject our null hypothesis.</u></em>

Therefore, we conclude that the true mean is greater than 10.

(b) Now, P-value of the test statistics is given by the following formula;

P-value = P( $t_3_4$ > 5.9028) = Less than 0.05% {using t table)

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