I think it’s 4952 but i’m not sure
Answer: The answer is your bad, you shouldnt be "answering" questions with " sorry i need points"
Answer:
The amount of water must be added to this task = 60 
Step-by-step explanation:
Let amount of water added = x 
Then from the given conditions
A chemist would like to dilute a 90-cc solution that is 5% acid to one that is 3% acid. So
90 (0.05) = 0.03 ( 90 + x )
4.5 = 2.7 + 0.03 x
0.03 x = 1.8
x = 60 
Therefore the amount of water must be added to this task = 60 
Let the number of large bookcases be x and number of small bookcases be y, then
Maximise P = 80x + 50y;
subkect to:
6x + 2y ≤ 24
x, y ≥ 2
The corner points are (2, 2), (2, 6), (3.333, 2)
For (2, 2): P = 80(2) + 50(2) = 160 + 100 = 260
For (2, 6): P = 80(2) + 50(6) = 160 + 300 = 460
For (3.333, 2): P = 80(3.333) + 50(2) = 266.67 + 100 = 366.67
Therefore, for maximum profit, he should produce 2 large bookcases and 6 small bookcases.
132/2 = 66
66/2 = 33
33/3 = 11
11/11 = 1
132 = 2^2 * 3 * 11
55121/11 = 5011
5011/5011 = 1
55,121 = 11 * 5011
LCM = common factor with larger exponent * not common factors
LCM = 2^2 * 3 * 11 * 5011
LCM = 661,452