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sashaice [31]
3 years ago
6

Can someone help me plz

Mathematics
2 answers:
iris [78.8K]3 years ago
5 0

SIMPLIFY TO A SINGLE POWER OF 6:

\dfrac{6^5}{6} = \dfrac{6^5}{6^1} = 6^{5-1} = 6^4

spayn [35]3 years ago
5 0

Answer:

6^4

Step-by-step explanation:

Since we aren't given a power in the denominator we can rewrite it as 6^1 since that equals 6 either way. Use the rule [ x^y/x^z = x^y-z ] to rewrite as a single power. Thus, 6^5-1 = 6^4.

Best of Luck!

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How do I solve this
Veronika [31]

Answer:

P(A or B) = 1.16

Step-by-step explanation:

Given probability:

Probability of event A = P(A) = 0.46

Probability of event B = P(B) = 0.7

P(A and B) = 0.43

Find:

P(A or B)

Computation:

If A is an incident and B is a separate event, P(A or B) is the possibility of either A, B, or both events occurring.

P(A or B) = P(A) + P(B)

P(A or B) = 0.46 + 0.7

P(A or B) = 1.16

5 0
3 years ago
14. Find the Error Hiroshi is determining -42 – (-37). Find his
vaieri [72.5K]

Answer:

Hiroshi's error was not having changed the sign of the number 37 by removing the parentheses and placing -37 instead of +37.

Step-by-step explanation:

we have

Hiroshi's work

42-(-37)=42-37=5

Remember that

a negative number is just a positive number multiplied by -1

and (-1)(-1)=+1

so

Correct work

42-(-37)

42-(-1)(37)

42-(1)(-1)(37)

42+(-1)(-1)(37)

=42+37=79

therefore

Hiroshi's error was not having changed the sign of the number 37 by removing the parentheses and placing -37 instead of +37.

3 0
3 years ago
When e = 4, f = 2, and g = 8If e varies jointly with f and g, what is the constant of variation?
tatyana61 [14]

Answer:

e=\frac{1}{4} fg

Step-by-step explanation:

Joint variation problem  solve using the equation y = kxz.

e ∝ fg

e=kfg

now substitute the values

4=k*2*8\\4=16k\\k=\frac{4}{16} \\k=\frac{1}{4}

The relationship will be:

e=kfg\\e=\frac{1}{4} fg

8 0
3 years ago
Read 2 more answers
Why aren't theories considered absolute truths?
Whitepunk [10]
They are not absolutely truths because they are not found to be truth of false they are things that are only a thing carried over they years and not know if they are the truth or if they are false
6 0
3 years ago
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Write an equation of the ellipse with foci at (0,+12) and vertices at (0,+13)
nekit [7.7K]
 To solve this problem you must apply the proccedure shown below:
 1. You have that the ellipse given as a vertical major axis (a=13), therefore, taking the ellipse with its center at the origin, you have the following equation:
 (y^2/a^2)+(x^2/b^2)=1
 2. You have the distance from the center of the ellipse to the focus:
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 b=√(13^3-12^2)
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 a^2=169
 b^2=25
 (y^2/169)+(x^2/25)=1
 The answer is: (y^2/169)+(x^2/25)=1 
6 0
3 years ago
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