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Allushta [10]
3 years ago
10

One quarter is 191/200 inch in diameter. Eight quarters are placed side by side. How many inches long is the line of quarters? G

ive your answer as a decimal.
Mathematics
1 answer:
alukav5142 [94]3 years ago
8 0
1 quarter is 191/200 inches......so 8 quarters is :
8 * 191/200 = 1528/200 = 7.64 inches long <==
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Yes! 4/5 is .8 and so is 8/10.
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I might give the crown
emmainna [20.7K]

Answer:

Area=88in squared

Step-by-step explanation:

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The blades of a windmill turn on an axis that is 40 feet from the ground. The blades are 15 feet long and complete 3 rotations e
astraxan [27]

Answer:

a is the _amplitude_(Length of the blades)_

The vertical shift, k, is the _Mill shaft height_

a = 15\ ft\\\\k = 40\ ft

y = 15sin(\frac{\pi}{10}t) + 40

Step-by-step explanation:

In this problem the amplitude of the sinusoidal function is given by the length of the blades.

a = 15\ ft

The mill is 40 feet above the ground, therefore the function must be displaced 40 units up on the y axis. So:

k = 40\ ft

We know that the blades have an angular velocity w = 3 rotations per minute.

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So:

w = \frac{3(2\pi)}{60}\ rad/s

w = \frac{\pi}{10}\ rad/s

Finally:

a is the _amplitude_(Length of the blades)_

The vertical shift, k, is the _Mill shaft height_

a = 15\ ft\\\\k = 40\ ft

y = 15sin(\frac{\pi}{10}t) + 40

3 0
4 years ago
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Given the functions f(x) = 4x2 − 1, g(x) = x2 − 8x + 5, and h(x) = –3x2 − 12x + 1, rank them from least to greatest based on the
tangare [24]

Answer:

Option D) h(x), f(x), g(x)

Step-by-step explanation:

we know that

The axis of symmetry of a vertical parabola is equal to the x-coordinate of the vertex of the parabola

Part 1) we have

f(x)=4x^{2} -1

This is a vertical parabola open upward

The vertex is a minimum The vertex is the point (0,-1)

The x-coordinate of the vertex is 0

so

The axis of symmetry is x=0

Part 2) we have

g(x)=x^{2}-8x+5

This is a vertical parabola open upward

The vertex is a minimum

Convert the equation into vertex form

g(x)-5=x^{2}-8x

g(x)-5+16=x^{2}-8x+16

g(x)+11=x^{2}-8x+16

g(x)+11=(x-4)^{2}

g(x)=(x-4)^{2}-11

The vertex is the point (4,-11)

The x-coordinate of the vertex is 4

so

The axis of symmetry is x=4

Part 3) we have

h(x)=-3x^{2}-12x+1

This is a vertical parabola open downward

The vertex is a maximum

Convert the equation into vertex form

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h(x)-1=-3(x^{2}+4x)

h(x)-1-12=-3(x^{2}+4x+4)

h(x)-13=-3(x+2)^{2}

h(x)=-3(x+2)^{2}+13

The vertex is the point (-2,13)

The x-coordinate of the vertex is -2

so

The axis of symmetry is x=-2

Part 4) Rank their axis of symmetry from least to greatest

1) h(x) -----> axis of symmetry -2

2) f(x) -----> axis of symmetry 0

3) g(x) -----> axis of symmetry 4

so

h(x),f(x),g(x)

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4 years ago
Help me pls TwT I’m really suck at school
andrey2020 [161]

Answer:

The answer is A.

Step-by-step explanation:

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3 years ago
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