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tino4ka555 [31]
2 years ago
11

PLS HELP ASAP

Mathematics
2 answers:
Rudik [331]2 years ago
4 0

Answer:

18+45m

Step-by-step explanation:

9x2= 18

9x5m= 45m

18+45m

azamat2 years ago
3 0
The answer is D

I got it roght on the assignment
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Simply the expression below <br><br> (10-3i)(2-5i)
scoundrel [369]

Answer:

7i and 3i

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3 years ago
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Given that g(x) = 2x ^ 2 - 2x + 8 , find each of the following. a) g(0) b) g(- 2) C) g(3) d) g(- x) e) g(1 - t)
raketka [301]

Answer:

g(-2)=20

Step-by-step explanation:

Given g(x)=2x^2-2x+8, substitute what is in the parentheses for x to find an output.

For g(-2), the term -2 is in the parentheses. Thus, substitute x=-2 into 2x^2-2x+8 to find g(-2):

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5 0
2 years ago
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Normal probability Density Function Use a graphing utility to graph the model probability density function with µ = 0 and ð = 2,
Nuetrik [128]

Answer:

Step-by-step explanation:

Hello!

The standard deviation (δ) is a measure of variability, this means, it shows how dispersed the data set is with respect to the mean. The population mean (μ) is a measurement of position. The three graphics have the same position μ=0 but their standard deviations change, this means, the form of their bells is different. The greater the value of the standard deviation, the more dispersed the data is you can see this graphically because the width of the bell will be greater.

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5 0
3 years ago
Copy the problem, mark the givens in the diagram. Given: CS ≅ HR, ∠CHS ≅ ∠HCR, ∠CSH ≅ ∠HRC, Prove: CR ≅ HS
Veseljchak [2.6K]

Explanation:

1. CS ≅ HR, ∠CHS ≅ ∠HCR, ∠CSH ≅ ∠HRC — given

2. ∆CRH ~ ∆HSC — AA similarity theorem

3. ∠SCH ≅ ∠RHC — corresponding angles of similar triangles are congruent

4. CH ≅ HC — reflexive property of congruence

5. ∆CRH ≅ ∆HSC — SAS congruence theorem

6. CR ≅ HS — CPCTC

6 0
3 years ago
Two cars, car X and car Y , start moving from the same point P on a cross intersection. Car X is travelling east and car Y is tr
agasfer [191]
Let the distance traveled by car X be x km 
<span>let the distance traveled by car Y by y km </span>
<span>their paths form a right-angled triangle. </span>
<span>Let the distance between them be D km </span>
<span>D^2 = x^2 + y^2 </span>
<span>2D dD/dt = 2x dx/dt + 2y dy/dt </span>
<span>dD/dt = (x dx/dt + y dy/dt)/D </span>

<span>at the given case: </span>
<span>x = 60, y = 80 , dx/dt = 80, dy/dt = 100 </span>
<span>D^2 = 60^2 + 80^2 = 10000 </span>
<span>D = 100 </span>

<span>dD/dt = (60(80) + 80(100))/100 </span>
<span>= 128 </span>
5 0
3 years ago
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