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Georgia [21]
3 years ago
14

Write an equation in which the quadratic expression 2x^2-2x-13 equals 0

Mathematics
1 answer:
torisob [31]3 years ago
8 0

Answer:

x = 3 and -2 are the two solutions.

Step-by-step explanation:

2x^2 -2x -12 = 0

First factor out a 2

2(x^2 - x - 6) = 0

2(x - 3)(x + 2) = 0

2 = 0 x - 3 = 0 x + 2 = 0

2 does not equal zero so this is an extraneous solution

x - 3 = 0 so x = 3

x + 2 = 0 so x = -2

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Simplify this algebraic expression.<br><br> z-4/4+8
AveGali [126]

Answer:

z+7

Step-by-step explanation:

use PEMDAS!

1. divide 4/4, which is 1. (z-1+8)

2. combine like terms! -1 and 8 are like terms, so add them together. (z+7)

3. after that, you have the answer!! z+7!!

3 0
3 years ago
Find the equation of the line that passes through the following lines points (0,-1) and (3,12).​
Temka [501]

Answer:

y=13/3x-1

Step-by-step explanation:

k=(y2-y1) /(x2-x1)

A(0,-1) x1=0,y1=-1

B(3,12) x2=3, y2=12

k=(12-(-1))/(3-0)

k=(12+1)/3

k=13/3

y-y1=k(x-x1)

y-(-1)=13/3(x-0)

y+1=13/3*x

y=13/3*x-1

8 0
3 years ago
What is the range of possible sizes for side x? the other two sides are 8.0 and 8.5
kirza4 [7]

Answer: 0.5 < x < 16.5.

Step-by-step explanation:

Given: Two sides of triangle: 8.0 units and 8.5 units

Measure of third side = x

According to the triangle's inequality,

  • Sum of any two sides > third side.    (i)
  • Difference between the sides < third side.    (ii)

If x is the third side, then

x < 8+8.5   [Using (i)]

i.e. x< 16.5  

Also, x > 8.5-8   [Using (ii)]

i.e. x> 0.5

Hence, Range of possible sizes for side x would be 0.5 < x < 16.5.

8 0
3 years ago
Write an<br> algebraic expression for the word expression.<br> The product of 8 and z
Law Incorporation [45]

Answer:

8z

Step-by-step explanation:

have a wonderful day....

5 0
3 years ago
What is the best first step for solving the equation 5 = 3x - 4? a. Add 4 to both sides of the equation. b. Subtract 4 from both
Brut [27]

Answer:

A. Add 4 to both sides of the equation.

Step-by-step explanation:

Isolate your variable by using inverse operations.

4 0
3 years ago
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