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Gwar [14]
2 years ago
10

To decorate 6 dozen cupcakes with red hot candies, Nan needs about 550 red hots. Which two sacks of candy would be the best buy?

plsss help me asap giving brainless and explain whay is that the answer.​
Mathematics
1 answer:
olasank [31]2 years ago
4 0

Answer:

Is there supposed to be a picture?

Step-by-step explanation:

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If cos theta is -5/13 and sin θ < 0, what is tan θ ?
tensa zangetsu [6.8K]
Take the right angled triangle  with sides 13, 12 and 5. sine theta will be 12/13

When sin theta < 0 and cos theta < 0  we are in the  third  quadrant  so sin theta will be -12/13

tan theta = sin theta / cos theta  = -5/13 /  -12/13   = -5*13 / -12*13 =  5/12
 
7 0
3 years ago
Y+5=2(x+1)<br><br><br> what is the slope for this Math
Stells [14]

Answer:

2

Step-by-step explanation:

The slope-intercept form is

y=mx+b, where m is the slope and b is the y-intercept.y=mx+bRewrite in slope-intercept form.Simplify 2(x+1).Apply the distributive property.

y+5=2x+2⋅1

multiply 2 by 1.

y+5=2x+2

y+5=2x+2

Move all terms not containing y to the right side of the equation.Subtract 5 from both sides of the equation.

y=2x+2−5

y=2x−3

the slope is the "m" so the slope is 2

7 0
3 years ago
What is the equation of the line that passes through the point (8, 8) and has a<br> slope of -22
Likurg_2 [28]

Answer:

Step-by-step explanation:

y - 8 = -22(x - 8)

y - 8 = -22x + 176

y = -22x + 184

7 0
3 years ago
Multiply by hundreds: 545 times 200
fiasKO [112]

Answer:

109000

Step-by-step explanation:

5 0
3 years ago
Find the standard form of the equation of the circle with endpoints of a diameter at the points (3,8) and (-7,2)
poizon [28]

(x+2)^{2}+(y-5)^{2}= 34

The equation of a circle in standard form is

(x-a)^{2}+(y-b)^{2}=r^{2}

where (a , b) are the coordinates of the centre and r is the radius

The centre is at the midpoint of the endpoints and the radius is the distance from the centre to either of the 2 endpoints

Using the midpoint formula

midpoint = [\frac{1}{2}(xx_{1}+x_{2}, \frac{1}{2}(y_{1}+y_{2}

where (x_{1},y_{1}=(3,8) and (x_{2},y_{2}=(-7,2)

centre = (\frac{1}{2}(3-7),\frac{1}{2}(8+2)) = (-2,5)

Calculate r using the distance formula

r = √(x_{2}-x_{1})²+(y_{2}-y_{1})²)

= √((3+2)²+(8-5)²) = √(25+9) = √34 ⇒ r² =(√34)² = 34

equation of circle is : (x+2)²+(y-5)² = 34


8 0
3 years ago
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