Answer:
7.5 hours
Step-by-step explanation:
Using the variable 't' for time, you can set up an equation to find out how long it will take the truck to catch up to the bus. Since the bus is traveling at 60mph and the truck is traveling 1 2/3 times faster, we need to first find the rate of the truck:
1
Using 't' and the knowledge that they will have traveled the same distance we the truck catches up to the bus and the fact that the truck left 3 hours later:
60t = 100(t - 3) or 60t = 100t - 300
Solve for 't': 60t - 100t = -300 or -40t = -300 so, t = 7.5 hours
Answer:
Below
Step-by-step explanation:
● x-20 = y+20 (1)
● 2(y-22) = x+22 (2)
This is a system of simulataneous equations
Let's simplify the expressions first
● x -20 = y + 20 (1)
Add 20 to both sides
● x -20 + 20 = y+20 +20
● x = y + 40 (1)
● 2(y-22) = x+22 (2)
● 2y - 44 = x +22
Substrat 22 from both sides
● 2y-44-22 = x+22-22
● 2y -66 = x (2)
This is the new system:
● x = y+40 (1)
● x = 2y-66 (2)
Substract (2) from (1)
● x-x = y+40-(2y-66)
● y+40-2y+66 = 0
● -y +106 = 0
● y = 106
Replace y with 106 in (1)
● x = y +40
● x = 106+40
● x = 146
So the solutions are (146,106)
1/7 *2 =2/7 take denominator with 1 over it and multiply by numerator
Answer:
c 2:1
Step-by-step explanation:
8/4=2
4/4=1
8:4 simplified is 2:1
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