Since all terms have an x in them, you can first factor that out, yielding:
f(x) = x(x² - 6x + 9)
Then you are looking for numbers that multiplied give 9 and added give -6, which is -3 and -3. So the final factorization is:
f(x) = x(x-3)²
Answer:
The answer is "Login complexity will be increased very exponentially".
Explanation:
In computer science, The password is also known as a series of characters, which allows you to use the validation process to validate any customer's privacy.
- It is normal usage of passwords that work together with a username to make it, it only accessible by the user, and to give the user accessibility to a computer, software or web page.
- If the password is more complex so, it is hard to learn, and it also provides login complexity, that's why we must use a less complex password.
Answer:
A
Explanation:
Update
The listview can be called an arbitrary amount of times, different items may be passed and the cell can go from empty to non-empty and the other way round. ListView creates about as many cells as you see on screen and fills them with items. E.g. scrolling or modifications of the items list or resizing of the ListView can result in updates.
To accomplish this without using a loop,
we can use math on a string.
Example:
print("apple" * 8)
Output:
appleappleappleappleappleappleappleapple
In this example,
the multiplication by 8 actually creates 8 copies of the string.
So that's the type of logic we want to apply to our problem.
<span>def powersOfTwo(number):
if number >= 0:
return print("*" * 2**number)
else:
<span>return
Hmm I can't make indentations in this box,
so it's doesn't format correctly.
Hopefully you get the idea though.
We're taking the string containing an asterisk and copying it 2^(number) times.
Beyond that you will need to call the function below.
Test it with some different values.
powersOfTwo(4) should print 2^4 asterisks: ****************</span></span>
