Question

Factor f(x)=x^3-6x^2+9x

Answer 1

Since all terms have an x in them, you can first factor that out, yielding:

f(x) = x(x² - 6x + 9)

Then you are looking for numbers that multiplied give 9 and added give -6, which is -3 and -3. So the final factorization is:

f(x) = x(x-3)²