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Setler [38]
2 years ago
9

Multiply ( 2 x – y ) ( 3 x + y )

Mathematics
2 answers:
dexar [7]2 years ago
7 0

(2x-y)(3x+y)\\\\=2x(3x+y) -y(3x+y)\\\\=6x^2 +2xy - 3xy -y^2\\\\=6x^2 -xy -y^2

Nikitich [7]2 years ago
3 0
Answer: 6x^2-xy-y^2.

Tell me if you want step by step!!

Hope this helped. :)
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The probability that a randomly selected 3-year-old male chipmunk will live to be 4 years old is 0.96516.
mezya [45]

Using the binomial distribution, it is found that there is a:

a) The probability that two randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.93153 = 93.153%.

b) The probability that six randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.80834 = 80.834%.

c) The probability that at least one of six randomly selected 3-year-old male chipmunks will not live to be 4 years old is 0.19166 = 19.166%. This probability is not unusual, as it is greater than 5%.

-----------

For each chipmunk, there are only two possible outcomes. Either they will live to be 4 years old, or they will not. The probability of a chipmunk living is independent of any other chipmunk, which means that the binomial distribution is used to solve this question.

Binomial probability distribution  

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 0.96516 probability of a chipmunk living through the year, thus p = 0.96516

Item a:

  • Two is P(X = 2) when n = 2, thus:

P(X = 2) = C_{2,2}(0.96516)^2(1-0.96516)^{0} = 0.9315

The probability that two randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.93153 = 93.153%.

Item b:

  • Six is P(X = 6) when n = 6, then:

P(X = 6) = C_{6,6}(0.96516)^6(1-0.96516)^{0} = 0.80834

The probability that six randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.80834 = 80.834%.

Item c:

  • At least one not living is:

P(X < 6) = 1 - P(X = 6) = 1 - 0.80834 = 0.19166

The probability that at least one of six randomly selected 3-year-old male chipmunks will not live to be 4 years old is 0.19166 = 19.166%. This probability is not unusual, as it is greater than 5%.

A similar problem is given at brainly.com/question/24756209

6 0
2 years ago
If im making 12 a hour and get a 10% increase how much more im making
Art [367]

Answer:

13.2/hour

Step-by-step explanation:

10% of 12 = 1.2

12+1.2=13.2

4 0
3 years ago
Y=f(x)=2x find f(x) when x=2
Rainbow [258]

Y=f(x)=2x find f(x) when x=2

Plug in

f(2)=2(2)  =4

Answer

4

3 0
3 years ago
Read 2 more answers
PLEASE HELP! DUE TODAY :))
Aleonysh [2.5K]

Step-by-step explanation:

do like the picture I sent

3 0
2 years ago
Find the measure of
AVprozaik [17]

Answer:

55

Step-by-step explanation:

since b is 110, you will have to divide 110 by 2 to find out the answer of c because its a half of b and that leaves you with 55, also a is 55 two

c=55

a=55

d=30

7 0
3 years ago
Read 2 more answers
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