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2 years ago

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The temperature at 1 pm was 88 degrees. By 4 pm, the temperature was 72 degrees. Determine the constant rate of change of the te

mperature.

1 answer:

Vladimir79 [104]2 years ago

6 0

The constant change of temperature was dropping by 16 degrees. Make sure to friend me and thank me

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Wesley does this work to find the decimal equivalent of 2399. What does his work tell you about the decimal equivalent?

MrMuchimi

answer is 2399

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1 year ago

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A fisherman traveled in a boat from point N upstream. After having traveled 6 km, he stopped rowing and 2 hour 40 min after firs

Nat2105 [25]

Answer:

The speed of the river's current is 4.5 km/hr.

Step-by-step explanation:

Given : A fisherman traveled in a boat from point N upstream.

After having traveled 6 km, he stopped rowing and 2 hour 40 min after first leaving N, he was brought back to N by the current.

Knowing that the speed of the boat in still water is 9 km/hour

To find : The speed of the river’s current.

Solution :

Let the speed of current = x km/h

Speed of boat = 9 km/h

Thus, the speed in upstream = (9 - x) km/h

Also, the speed in downstream = x km/h (because the boat is stationary in downstream)

Total distance = 6 km ( from N to the point he reached )

Total time = 2 hours 40 minutes

$\text{2 hours 40 minutes}=2\frac{40}{60}=2 \frac{2}{3} \\\\\text{2 hours 40 minutes}=\frac{8}{3} \text{ hours}$

We know, $\text{Time} = \frac{\text{Distance}}{\text{Speed}}$

According to the question,

$\frac{6}{9-x}+\frac{6}{x}=\frac{8}{3}$

Taking LCM and 6 common

$6[\frac{x+9-x}{(9-x)x}]=\frac{8}{3}$

Take 6 to another side,

$\frac{9}{9x-x^2}=\frac{8}{3\times 6}$

Cross multiply,

$9\times 18=8\times(9x-x^2)$

$162=72x-8x^2$

Taking 4 common and cancel out

$4x^2-36x+81=0$

Solve quadratic equation by middle term split,

$4x^2-18x-18x+81=0$

$2x(2x-9)-9(2x-9)=0$

$(2x-9)(2x-9)=0$

$\Rightarrow 2x-9=0$

$\Rightarrow x=\frac{9}{2}=4.5$

Therefore, The speed of the river's current is 4.5 km/hr.

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2 years ago

Find the range and interquartile range of the data.

shutvik [7]

I believe the range is the middle number so start from 63 then 46 then 53 then go back and forth until you get the middle number now after you get the middle number for the IQR add up both sides of the middle and / by the all the number on the left and right of the middle number

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2 years ago

A short necklace has 32 gold beads and 8 black beads.

Katena32 [7]

I think there are 12
so there are 40 beads on the short one
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2 years ago

Im really struggling. please help me <br>

Wittaler [7]

Answer:

A. x=6 B. x=4.5 C. x-35 D. x=13

Step-by-step explanation:

For A and B, divide the numbers you have. For C and D, multiply the numbers you have.

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2 years ago

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