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RideAnS [48]
2 years ago
12

The temperature at 1 pm was 88 degrees. By 4 pm, the temperature was 72 degrees. Determine the constant rate of change of the te

mperature.
Mathematics
1 answer:
Vladimir79 [104]2 years ago
6 0
The constant change of temperature was dropping by 16 degrees. Make sure to friend me and thank me
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The minute hand on an analog clock is 8 inches long. how far does the tip of the minute hand travel in 16 minutes
Dahasolnce [82]
We know that
<span>on an analog clock
60 minutes is equal to a circumference of 360</span>°
so
360/60-----> 6°
that means 
1 minute is equal to --------> 6°
16 minutes----------> X
x=16*6-----> 96°

the length of a circumference=2*pi*r
for r=8 in

the length of a circumference=2*pi*8-----> 50.24 in

if 360° (full circle) has a length of----------------> 50.24 in
  96°---------------------------> x
x=96*50.24/360------> x=13.40 in

the answer is
13.40 in

5 0
2 years ago
What is the constant rate of change of (5,80) (4,64) and (6,96)
sveticcg [70]

Answer:

16

Step-by-step explanation:

The existence of the constant rate of change is given the ratio of y to x is the same. Then:

k_{1} = \frac{80}{5}

k_{1} = 16

k_{2} = \frac{64}{4}

k_{2} = 16

k_{3} = \frac{96}{6}

k_{3} = 16

In consequence, the constant rate of change is 16.

8 0
2 years ago
Midpoint (2,5) (-1,9)
Natasha_Volkova [10]

The midpoint of the 2 points is (0.5, 7)

Hope this helps you

-AaronWiseIsBae

4 0
3 years ago
Please please help, i will mark the brainliest
Bumek [7]

Answer:

58

Step-by-step explanation:

i think this is the right answer. Not sure

6 0
2 years ago
Read 2 more answers
Please help me in the box below
Fynjy0 [20]
1.330
2.930
3.30
4.80
5.90
6.140
7.10
8.110
6 0
3 years ago
Read 2 more answers
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