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3 years ago

12

The temperature at 1 pm was 88 degrees. By 4 pm, the temperature was 72 degrees. Determine the constant rate of change of the te

mperature.

1 answer:

Vladimir79 [104]3 years ago

6 0

The constant change of temperature was dropping by 16 degrees. Make sure to friend me and thank me

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suppose a farmer has six cows and each cow has six calves the first year, they all increase in the same propotion, to the end of

Sergio [31]

Hi!

To solve this question you need to solve 7^8 x 6

7^8 = 5,764,801

5,764,801 x 6 = 34,588,806

4 0

3 years ago

!!!!!! URGENT PLS HELP ME ANSWER !!!!

laila [671]

Answer:

1) A = 547.1136, C = 82.896

2) A = 678.5226, C = 92.316

3) A = 844.5344, C = 102.992

4) A = 1554.49625, C = 139.73

5) A = 1561.4906, C = 140.044

6) A = 994.8776, C = 111.784

Step-by-step explanation:

1)

$A = \Pi (\frac{D}{2})^2 = 3.14 * (\frac{26.4}{2})^2 = 3.14 * 13.2^2 = 547.1136$

$C = \Pi D = 3.14 * 26.4 = 82.896$

2)

$A = \Pi r^2 = 3.14*(14.7)^2 = 678.5226$

$C = 2\Pi r = 14.7*2 * 3.14 = 92.316$

3)

$A = \Pi (\frac{D}{2})^2 = 3.14 * (\frac{32.8}{2})^2 = 3.14 * 16.4^2 = 844.5344$

$C = \Pi D = 3.14 * 32.8 = 102.992$

4)

$A = \Pi (\frac{D}{2})^2 = 3.14 * (\frac{44.5}{2})^2 = 3.14 * 22.25^2 = 1554.49625$

$C = \Pi D = 44.5*3.14 = 139.73$

5)

$A = \Pi r^2 = 3.14*22.3^2 = 1561.4906$

$C = 2\Pi r = 2 * 3.14 * 22.3 = 140.044$

6)

$A = \Pi r^2 = 3.14 * 17.8^2 = 994.8776$

$C = 2\Pi r = 2 * 3.14 * 17.8 = 111.784$

8 0

3 years ago

Find the derivative.

krek1111 [17]

Answer:

$\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

General Formulas and Concepts:

<u>Algebra I</u>

Terms/Coefficients

Expanding/Factoring

<u>Calculus</u>

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]: $\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

$\displaystyle f(x) = \frac{\sqrt{x}}{e^x}$

<u>Step 2: Differentiate</u>

Derivative Rule [Quotient Rule]: $\displaystyle f'(x) = \frac{(\sqrt{x})'e^x - \sqrt{x}(e^x)'}{(e^x)^2}$
Basic Power Rule: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}(e^x)'}{(e^x)^2}$
Exponential Differentiation: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{(e^x)^2}$
Simplify: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{e^{2x}}$
Rewrite: $\displaystyle f'(x) = \bigg( \frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x \bigg) e^{-2x}$
Factor: $\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0

2 years ago

The tea chest needs to send the sales tax that it has collected to the state. The total sales, including 4% sales tax are $7115.

Elina [12.6K]

.04*7115.68=284.6272

$284.62 or $284.63 (depending on how lenient your teacher is with rounding)

8 0

3 years ago

9. Determine whether (-3,2) is a solution of<br> Y = 2x +8<br> Y= -X+1

miss Akunina [59]

2 = 2(-3) + 8
2 = -6 + 8
2 = 2

true.

2 = 3 + 1
2 = 4

false.

this is not a solution because both equations have to be true.

4 0

2 years ago