What is the scale factor of the dilation applied to Δ DEF to produce Δ D'E'F'? (Hint: Does it get bigger or smaller?
1 answer:
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Answer:
The height of the ball after 3 secs of dropping is 16 feet.
Step-by-step explanation:
Given:
height from which the ball is dropped = 160 foot
Time = t seconds
Function h(t)=160-16t^2.
To Find:
High will the ball be after 3 seconds = ?
Solution:
Here the time ‘t’ is already given to us as 3 secs.
We also have the relationship between the height and time given to us in the question.
So, to find the height at which the ball will be 3 secs after dropping we have to insert 3 secs in palce of ‘t’ as follows:
h(3)=160-144
h(3)=16
Therefore, the height of the ball after 3 secs of dropping is 16 feet.
You just have to plug your coordinates into the distance formula.
(1, 6) (8, 1)
(X1, Y1) (X2, Y2)
do the work and you get 8.6
(1, 6) (8, 1)
(X1, Y1) (X2, Y2)
do the work and you get 8.6