Answer:
The approximate length of segment EF is 7 unit
Step-by-step explanation:
Given figure is the graph having E and F coordinate
The coordinate of point E = ( 
, 
) = ( - 2 , -4 )
The coordinate of point F = ( 
, 
) = ( 2 , 2 )
Let The distance between the points E and F = D
So, D = 
or, D = 
Or, D = 
or, D = 
∴ D = 
I.e D = 7.21 unit
So, Approximate value of D = 7 unit
Hence The approximate length of segment EF is 7 unit . Answer
Answer:
150+79m
Step-by-step explanation:
$150+$79m (m per month)
Answer:
34 + 8n
Step-by-step explanation:
a₁ = 42
a₂ = a₁ + 8 = 42 + 8 = 50
a₃ = a₂ + 8 = 50 + 8 = 58
a₄ = a₃ + 8 = 58 + 8 = 66
Arithmetic sequence: 42, 50 , 58 , 66, ......
a₁ = 42 ; d = 8
= a₁ + d(n-1)
= 42 + 8(n - 1)
= 42 + 8n - 8
= 34 + 8n
<span>Let x=0.8888...
x=0.8888 Start with the given equation
10x=8.8888 Multiply both sides by 10. The goal is to move the decimal point to the next repeating portion (which is just one spot to the right)
Now subtract the equation x=0.8888 from 10x=8.8888 to get
10x-x=8.8888-0.8888
9x=8 Combine like terms. Notice how the decimal portions cancel out.
x=8/9 Divide both sides by 9 to isolate x
So the answer is x=8/9 which means that 8/9=0.8888 (where the 8's repeat)</span>
100 to 49. Because area is units squared, and it is finding by multiplying the side lengths, you would simply square the ratio.
