Answer:
Step-by-step explanation:
Slope of a line passing through two points 
and 
is given by the formula,
Slope = 
Slope of the line PQ passing through the two points P(-8, 2) and Q(4, 2) will be,
Slope '
' = 
= 0
Therefore, slope of the line PQ parallel to the x-axis = 0
Slope of the line MN passing through the points M(8, 6) and N(8, -8) is,
Slope '
' = 
= ∞
Therefore, slope of the line MN parallel to y-axis is undefined.
Since, angle between the x-axis and y-axis is 90°,angle at the intersection point between the lines parallel to x and y axis will be 90°.
These lines are perpendicular to each other.
Answer:
Step-by-step explanation:
Exponential functions are the inverses of logarithmic functions, and vice versa.
Play usually continues 7.Qf3+ Ke6 8.Nc3 (see diagram). Black will play 8...Nb4 or 8...Ne7 and follow up with c6, bolstering his pinned knight on d5. If Black plays 8...Nb4, White can force the b4 knight to abandon protection of the d5 knight with 9.a3?! Nxc2+ 10.Kd1 Nxa1 11.Nxd5, sacrificing a rook, but current analysis suggests that the alternatives 9.Qe4, 9.Bb3 and 9.O-O are stronger. White has a strong attack, but it has not been proven yet to be decisive.
Because defence is harder to play than attack in this variation when given short time limits, the Fried Liver is dangerous for Black in over-the-board play, if using a short time control. It is also especially effective against weaker players who may not be able to find the correct defences. Sometimes Black invites White to play the Fried Liver Attack in correspondence chess or in over-the-board games with longer time limits (or no time limit), as the relaxed pace affords Black a better opportunity to refute the White sacrifice.
Answer:
the answer is 4
Step-by-step explanation:
