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3 years ago

Find the positive number which when multiplied by itselfs givs 11025

Mathematics

1 answer:

xxTIMURxx [149]3 years ago

8 0

To do this, take the square root of 11025.
Using a calculator, you can find the positive number to be 105.

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How do I write 0.632 in expanded word form?

Leno4ka [110]

0.632 in expanded word form is six hundred thirty two thousandths

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4 years ago

Read 2 more answers

Add. -85.53+(-41.00) A. -126.53 B. -44.47 C. 44.53 D. 126.47

Rashid [163]

The correct answer is A

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3 years ago

A street sign is 7 feet 2 inches tall. How tall is it in inches?

Ulleksa [173]

Answer:

86 inches

Step-by-step explanation:

7 feet •12 inches= 84 inches

84 in. + 2 in. = 86 in.

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3 years ago

I need help with this ASAP please help. Look at the picture

atroni [7]

I am not entirely sure if this is correct, so forgive me if I am wrong

(┬┬﹏┬┬)

Answer: 266,667 bottles

Step-by-step explanation:

80/300 people preferred soft drink z. This as a decimal is 0.2666

This means that out of the million, 0.2666666666666667% need to be soft drink z

1,000,000x0.2666666666666667 =266,666.667

This can be rounded to 266,667 bottles of soft drink z

(I chose to include the whole decimal for the most accurate results, and save rounding for the last step)

6 0

3 years ago

A construction company employs two sales engineers. Engineer 1 does the work of estimating cost for 70% of jobs bid by the compa

netineya [11]

Answer:

Engineer 1

Step-by-step explanation:

Based on the information given:

P( 1 ) = 0.7

P( 2 ) = 0.3

P(A | B) is a conditional probability: the likelihood of event A occurring given that B is true.

P( E | 1 ) = 0.02

P( E | 2 ) = 0.04

Then P( E | 1 ) is the probability that an error occurs when engineer 1 does the work and P( E | 2 ) is the probability that an error occurs when engineer 2 does the work.

To have an idea of which engineer is more likely to do the work when an error occurs you need to calculate P( 1 | E ) and P( 2 | E ), The probability that engineer 1 does the work when an error occurs and the probability that engineer 2 does the work when an error occurs.

The Bayes's theorem states:

$P( B | A ) = \frac{P( A | B )*P( A )}{P( B )}$

Using the notation above:

$P( 1 | E ) = \frac{P( E | 1 )*P( 1 )}{P( E )}$

P( E ) = 0.7*0.02 + 0.3*0.04 = 0.026 /// the probability that engineer 1 does the work and an error occurs or the probability that engineer 2 does the work and an error ocurrs.

$P( 1 | E ) = \frac{0.04*0.3}{0.026}=0.538$

Doing the same for engineer 2:

$P( 2 | E ) = \frac{0.04*0.3}{0.026}=0.462$

6 0

3 years ago