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3 years ago

What is the term for the point where angle bisectors of a triangle meet

Mathematics

2 answers:

OLga [1]3 years ago

6 0

This point is called the incenter.

Yuliya22 [10]3 years ago

3 0

The incenter which has trilinear coordinates.

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What else would need to be congruent to show that abc = xyz by asa

pochemuha

Since you're working with the ASA postulate, you're looking to show congruence of the angles at either end of a side. You're given side AC and angle A as congruent with their counterparts. Obviously, you also need to show congruence of angle C with its counterpart, angle Z.

selection B is appropriate

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3 years ago

I will mark you brainliest!!

lakkis [162]

Answer:

Alternate-exterior angles theorem.

Step-by-step explanation:

Two parallel lines are cut by a transversal, and if there are a pair of congruent angles that are outside of the parallel lines, and on opposite sides of the transversal, you will have the alternate-exterior angles theorem.

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3 years ago

The double number line shows that 5 kilograms of avocados cost $9 dollar

svlad2 [7]

Answer:

1.8.

Step-by-step explanation:

9 divided by 5 is 1.8.

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3 years ago

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I really need help quickly please!!!!

Vladimir [108]

Answer:The third one is!!

Step-by-step explanation:

The commutative property of addition says that changing the order of addends does not change the sum. Here's an example: 4 + 2 = 2 + 4 4 + 2 = 2 + 4 4+2=2+4

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3 years ago

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In a circle, area and circumference can be found using the formulas A=(pi)r^2 and C=2(pi)r, respectively, Write a formula for A

AURORKA [14]

Answer:

$A = \dfrac{C^2}{4\pi}$

Step-by-step explanation:

Given that

Area of a circle $A=\pi r^2$

Circumference of the circle $C = 2 \pi r$

Let us re-write the equation of area of circle:

$A=\pi r^2$

$A = \pi \times r \times r$

Multiplying and dividing with 2:

$A = \dfrac{2\pi r}{2} \times r\\\text{Putting }2\pi r = C:\\\Rightarrow A = \dfrac{C}{2} \times r\\\text{Multiplying and dividing by } 2\pi:\\\Rightarrow A = \dfrac{C}{2} \times \dfrac{2\pi r}{2\pi}\\\text{Putting }2\pi r = C:\\\Rightarrow A = \dfrac{C \times C}{4 \pi}\\\Rightarrow A = \dfrac{C^2}{4 \pi}$

Hence, <em>A</em> in terms of <em>C</em> can be represented as:

$A = \dfrac{C^2}{4\pi}$

4 0

3 years ago