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Serjik [45]
4 years ago
12

What is the multiplier 5/7=30/42

Mathematics
1 answer:
vaieri [72.5K]4 years ago
4 0

Answer:

The multiplier is 1

Step-by-step explanation:

The multiplier is 1.

Lets assume that the multiplier is x

So,

5/7 * x = 30/42

Multiply both sides by 7/5

7/5 * 5/7 k = 30/42 * 7/5

x= 6/6

This implies that:

5/7 * 6/6 = 30/42

Thus the multiplier is 1....

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Answer:

C. They are similar because their corresponding angles are congruent and their corresponding side lengths are proportional.

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What is greater 413,005 or 62,910
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412,005 and 62,910 the number you are looking for is greater than them is 1112,9328 is greater than 413,005 and 62,910
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Use the normal distribution to approximate the following binomial distribution. A recent survey indicated that 55% of the people
madam [21]

Answer:

0.86 (Approx)

Step-by-step explanation:

Given:

n = 35

P = 55% = 0.55

Q = 1 - p = 0.45

Computation:

Standard deviation σ = √npq

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Standard deviation σ = 2.9432

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p[(x-np)/ σ ]

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3 years ago
The personnel department of a large corporation wants to estimate the family dental expenses of its employees to determine the f
Verizon [17]

Answer:

CI(95%): [205,5;400.8]dolars

Step-by-step explanation:

Hello!

So you need to construct a confidence interval for the average family dental expenses (μ) using the sample given in the problem. To estimate it you need to first choose a statistic. For this small sample, considering that the variable has a normal distribution (I made a quick Shapiro Wilks test, with p-value 0.3234, you can assume normality) the best statistic to use is the Student's t-test.

t= [x(bar)-μ]/S/√n ≈ t₍ₙ₋₁₎

The formula for the confidence interval to estimate the mean is

x(bar)±t_{n-1; 1-\alpha/2}* (S/√n)

<u>The critical value is from a t-distribution with 11 degrees of freedom </u>

±t_{n-1; 1-\alpha/2} = t_{11; 0.975} = 2.201

<em> >remember since it's two-tailed, to get the right critical value you have to divide α by 2. So in the text, you received a confidence level of 1-α=0.95 so α=0.05 then α/2=0.025 and 1-α/2=0.975</em>

To construct the interval, you need to first calculate the sample mean and the standard derivation.

<u>Sample</u>

115; 370; 250; 593; 540; 225; 117; 425; 318; 182; 275; 228

n= 12

∑xi = 3638 ∑xi² = 1362670

<u>Sample mean</u>

x(bar): (∑xi)/n = 3638/12 = 303.17 dolars

<u>Standard derivation</u>

S²= 1/n-1*[∑xi²- (∑xi)²/n] = 1/11 * [1362670-((3638)²/12)] = 23614.47 dolars²

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<u>Confidence interval (95%)</u>

303.17± 2.201* (153.67/√12)

[205,5;400.8]dolars

I hope you have a SUPER day!

3 0
4 years ago
Mala has a collection of bangles. She has 20 gold bangles and 10 silver bangles. What is the percentage of bangles of each type?
Rainbow [258]

Answer:

Percentage of gold bangles is 66.6 and of silver bangles it is 33.3

Step-by-step explanation:

Given:

Number of gold bangles Mala has = 20

Number of silver bangles she has  = 10

Total number of bangles = 20+10 = 30

We have to find the percentage of each type of bangles.

So,

Percentage of bangles  = \frac{No.\ of \ bangles\ each\ type}{Total\ no.\ of \ bangles} \times 100

  • Percentage of gold bangles.

        ⇒ \frac{20}{30} \times 100

        ⇒ \frac{20\times 100}{30}

        ⇒ \frac{2000}{30}

        ⇒ \frac{200}{3}

        ⇒ 66.6\%

  • Percentage of silver bangles.

       ⇒ \frac{10}{30}\times 100

       ⇒ 33.3\%

Percentage of gold bangles, Mala has = 66.6 and of silver bangles it is = 33.3

7 0
3 years ago
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