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3 years ago

Does 2 1/3-1 3/4 need require renaming

Mathematics

1 answer:

ANEK [815]3 years ago

6 0

Answer:

$\frac{7}{12}$

Step-by-step explanation:

$2 \frac{1}{3} - 1 \frac{3}{4}$

The fractions above are known as mixed numbers (that is, fractions that contain the combination of a whole number and proper fraction). The mixed numbers can equally be renamed as improper fractions. However, renaming can only occur the the mixed numbers are being transformed as below:

$\frac{7}{3} - \frac{7}{4}$

The transformation occur through a simple approach thus: for the first mixed number; 2 1/3 = 2 multiplied by 3 plus 1 divide by 3 equals 7/3. Similarly, mixed number 1 3/4 is transformed by this: 1 multiplied by 4 plus 3 divide by 4 equals 7/4.

Simplifying further to arrive at final result implies,

$\frac{7}{3} - \frac{7}{4}$

Take the LCM of the denominators (4 × 3 =12) and simplify thus:

$= \frac{28 - 21}{12}$

$= \frac{7}{12}$

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Solve the following logarithmic equations. ln(32x^2) − 3 ln(2) = 3

Kazeer [188]

Answer:

$x=\pm \frac{\sqrt{e^{3} } }{2}$

Step-by-step explanation:

Rewrite the equation using the next propierties:

$log(\frac{1}{x} )=-log(x)$

$ylog(x)=log(x^{y} )$

$log(x*y)=log(x)+log(y)$

$ln(32x^{2} )-ln(2^{3})=3\\ ln(32x^{2} )+ln(\frac{1}{2^{3} } )=3\\ln(\frac{32x^{2} }{8})=3\\ ln(4x^{2} )=3$

Cancel logarithms by taking exp of both sides:

$e^{ln(4x^{2}) } =e^{3} \\4x^{2} =e^{3}$

Divide both sides by 4:

$x^{2} =\frac{e^{3} }{4}$

Take the square root of both sides:

$x=\pm \sqrt{\frac{e^{3} }{4} } =\pm \frac{\sqrt{e^{3} } }{2}$

6 0

3 years ago

Is y=1/4xto the power of .05a power function

masha68 [24]

If you mistyped the question and you meant y=1/4x to the power of 0.5X then yes it's a function, but if you didint mistyped it then no because it cannot be graphed

8 0

3 years ago

Read 2 more answers

What is 11/12 minus 7/9 equal

julia-pushkina [17]

Answer:

5/36

Step-by-step explanation:

We need the least common denominator for 12 and 9.

12 = 2^2 * 3

9 = 3^2

LCD = 2^2 * 3^2 = 4 * 9 = 36

11/12 - 7/9 = 33/36 - 28/36 = 5/36

5 0

3 years ago

Suppose that it rains in Spain an average of once every 10 days, and when it does, hurricanes have a 8% chance of happening in H

Law Incorporation [45]

Answer:

The probability that it rains in Spain when hurricanes happen in Hartford is 0.1127

Step-by-step explanation:

This is a question where you use must use Bayes' Theorem.

The easiest way to do Bayes' type questions is to carefully define your terms.

Let R be the event that it is raining in Spain. R' is the event it isn't.

Let H be the event that it is hurricane in Hartford. H' is the event it isn't.

We know

P(R) = 1/10,

P(H | R) = 0.08,

P(H | R') = 0.07 and we want P(R | H).

Bayes Theorem says P(R | H) = [P(H | R)×P(R)] / P(H)

where

P(H) = P(H | R)×P(R) + P(H | R')×P(R')

Therefore,

P(R | H) = [P(H | R)×P(R)] / [P(H | R)×P(R) + P(H | R')×P(R')]

P(R | H) = [0.08 × 1/10] / [(0.08 × 1/10) + (0.07 × (1 - 1/10)]

P(R | H) = 8 / 71

P(R | H) = 0.1127

Therefore, the probability that it rains in Spain when hurricanes happen in Hartford is 0.1127.

7 0

3 years ago

Divide up the number 480 in a 3:5 ratio.

Naily [24]

Step-by-step explanation:

Hers your answer friend

4 0

4 years ago

Read 2 more answers