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galben [10]
3 years ago
13

What is the rate of change between (2,2) and (17,7)

Mathematics
1 answer:
choli [55]3 years ago
5 0

Answer:

1/3

Step-by-step explanation:

(7-2)/(17-2)=5/15=1/3

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On a bicycle trail, the city is painting arrows like the one shown below:
Marina CMI [18]

Answer:

134

Step-by-step explanation:

1. seperate the rectangle bottom and the triangle top

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3 years ago
 Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III
vodka [1.7K]

Given:

\sin x=-\dfrac{15}{17}

x lies in the III quadrant.

To find:

The values of \sin 2x, \cos 2x, \tan 2x.

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others  are negative.

We know that,

\sin^2 x+\cos^2 x=1

(-\dfrac{15}{17})^2+\cos^2 x=1

\cos^2 x=1-\dfrac{225}{289}

\cos x=\pm\sqrt{\dfrac{289-225}{289}}

x lies in the III quadrant. So,

\cos x=-\sqrt{\dfrac{64}{289}}

\cos x=-\dfrac{8}{17}

Now,

\sin 2x=2\sin x\cos x

\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})

\sin 2x=-\dfrac{240}{289}

And,

\cos 2x=1-2\sin^2x

\cos 2x=1-2(-\dfrac{15}{17})^2

\cos 2x=1-2(\dfrac{225}{289})

\cos 2x=\dfrac{289-450}{289}

\cos 2x=-\dfrac{161}{289}

We know that,

\tan 2x=\dfrac{\sin 2x}{\cos 2x}

\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}

\tan 2x=\dfrac{240}{161}

Therefore, the required values are \sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}.

7 0
3 years ago
Depth: 1.8 m Width: 2.5 m Height: 2 m What is the cuboid's volume?
8090 [49]

Answer:

9 m³

Step-by-step explanation:

The formula for calculating the volume (V) of a cuboid is

V = depth × width × height

  = 1.8 × 2.5 × 2 = 9 m³


5 0
3 years ago
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