This is a simultaneous question.
To solve this, we have to make up 2 equations based on the info provided like so:
electricity = e
gas = g
600e + 100g = $412 ——(1)
400e + 150g = $293 ——(2)
In this case, it’ll be easier to use the elimination method where you eliminate a variable so you can calculate only one.
Here, we will be eliminating e so we can get the cost of gas.
To do this we need to get both equation’s e to 600, so we have to multiply equation 2 by 1.5:
(2) x 1.5:
400e + 150g = $293
600e + 225g = $439.50 ——(3)
Now we eliminate e by subtracting equation 1 from equation 3:
(3) - (1):
600e + 225g - 600e - 100g = $439.50 -$412
125g = $27.50
g = $0.22.
Therefore one unit of gas costs $0.22.
Hope it helps and have a good day ahead :D
Answer:
Step-by-step explanation:
From the given information:
The domain D of integration in polar coordinates can be represented by:
D = {(r,θ)| 0 ≤ r ≤ 6, 0 ≤ θ ≤ 2π) &;
The partial derivates for z = xy can be expressed as:
Thus, the area of the surface is as follows:
![= 2 \pi \times \dfrac{1}{3} \Bigg [ (37)^{3/2} - 1 \Bigg]](https://tex.z-dn.net/?f=%3D%202%20%5Cpi%20%5Ctimes%20%5Cdfrac%7B1%7D%7B3%7D%20%20%5CBigg%20%5B%20%2837%29%5E%7B3%2F2%7D%20-%201%20%5CBigg%5D)
![= \dfrac{2 \pi}{3} \Bigg [37 \sqrt{37} -1 \Bigg ]](https://tex.z-dn.net/?f=%3D%20%5Cdfrac%7B2%20%5Cpi%7D%7B3%7D%20%5CBigg%20%5B37%20%5Csqrt%7B37%7D%20-1%20%5CBigg%20%5D)
Answer:
(3.5, 17)
Step-by-step explanation:
It would be nice to see the whole graph, so we can see where the functions cross.
Without that information, we can still eliminate unreasonable choices.
A) the quadratic at y=3.5 is well above the exponential
B) the most likely choice (3.5, 17)
C) at x=-8, the quadratic is above the exponential
D) neither graph goes anywhere near y = -8
F(x)=x-4
<span>x f(x)
3 –1
4 0
5 1
6 2</span>
