Answer:
continue to multiply to extend the table to whatever length you need
Step-by-step explanation:
powder water
5 8
10 16
15 24
Answer:
The possible approximate frequencies of the guitar string are 516.82 Hz and 508.82 Hz
Step-by-step explanation:
The given period of the tuning fork, T₁ = 1.95 × 10⁻³ s
The number of beats in 6.0 s = 24 beats
Therefore, the beat frequency,
= 4 beats per second = 4 Hz
Let f₁ represent the frequency of the tuning fork, and let f₂ represent the frequency of the guitar string, we have;
f₁ = 1/T₁ = 1/(1.95 × 10⁻³) ≈ 512.82 Hz
We have;
![f_{beat} = \left | f_2 - f_1 \right |](https://tex.z-dn.net/?f=f_%7Bbeat%7D%20%3D%20%5Cleft%20%7C%20f_2%20-%20f_1%20%5Cright%20%7C)
![\pm f_{beat} = f_2 - f_1](https://tex.z-dn.net/?f=%5Cpm%20f_%7Bbeat%7D%20%3D%20f_2%20-%20f_1)
Therefore, we get;
![4 \, Hz= \left | f_2 - 512.82 \, Hz \right |](https://tex.z-dn.net/?f=4%20%5C%2C%20Hz%3D%20%5Cleft%20%7C%20f_2%20-%20512.82%20%5C%2C%20Hz%20%5Cright%20%7C)
f₂ - 512.82 = ± 4
∴ f₂ = 512.82 ± 4
The possible frequencies of the guitar string, f₂ ≈ 516.82 Hz or f₂ ≈ 508.82 Hz
Answer:
sorry i cant help
Step-by-step explanation:
I hope this helps you out