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Wittaler [7]
3 years ago
5

Balancing the equations

Mathematics
1 answer:
erastovalidia [21]3 years ago
8 0
The first one is 1, 1, 1. the second one is 3, 4, 1, 4.
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Kaylis [27]
Three divided by two
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4 years ago
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Mary has a collection of nickels and quarters for a total value of 4.90.if she has 42 coins total how many of each kind are ther
Ray Of Light [21]

Let x be the number of nickels and y be the number of quarters.

Then, x + y = 42 --- (1)

It is given that total value = 4.90.

Therefore, 0.05x + 0.25y = 4.9 --- (2)

Multiply (1) by 0.25

0.25x + 0.25y = 10.5 --- (3)

Now, subtract (2) from (3), we get,

0.2x = 5.6

Divide both sides by 0.2.

x = 28

x + y = 42

y = 42 - x

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Hence, Mary has 28 nickels and 14 quarters in total.

7 0
3 years ago
(x5 + y5) ÷ (x + y) please answer ASAP
Shkiper50 [21]

Answer:

\frac{x^5+y^5}{x+y}=x^4-x^3y+x^2y^2-xy^3+y^4

Step-by-step explanation:

Given the expression

\left(x^5+y^5\right)\div \left(x+y\right)

\mathrm{Apply\:factoring\:rule:\:}x^n+y^n=\left(x+y\right)\left(x^{n-1}-x^{n-2}y+\:\dots \:-\:xy^{n-2}\:+\:y^{n-1}\right)\:\quad \quad \mathrm{n\:is\:odd}

x^5+y^5=\left(x+y\right)\left(x^4-x^3y+x^2y^2-xy^3+y^4\right)

=\frac{\left(x+y\right)\left(x^4-x^3y+x^2y^2-xy^3+y^4\right)}{x+y}

Cancel the common factor: x+y

=x^4-x^3y+x^2y^2-xy^3+y^4

Thus,

\frac{x^5+y^5}{x+y}=x^4-x^3y+x^2y^2-xy^3+y^4

3 0
3 years ago
Change 53/5 from an improper fraction to a mixed number.
Ilya [14]

Answer:

10.6

Step-by-step explanation:

53/5

7 0
3 years ago
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Which function is equivalent to y = 16^0.5x?
Varvara68 [4.7K]
16^.5 =4
1/2 power is the same as square root
So y = 4x
5 0
3 years ago
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