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3 years ago

A chef prepared five chocolate tortes for a dinner party. The guests consumed 2 5/16 tortes. How many

2 answers:

8 0

$5 - 2\frac{5}{16} = \frac{80}{16} - \frac{37}{16} = \frac{43}{16}\\\\=\boxed{\bf{2\frac{11}{16}}}$

Your final answer is D. 2 ¹¹/₁₆.

Alenkinab [10]3 years ago

3 0

If you would like to know how many tortes are left, you can calculate this using the following steps:

five chocolate tortes - 2 5/16 tortes = 5 - 2 5/16 = 5 - 37/16 = 80/16 - 37/16 = 43/16 = 2 11/16

The correct result would be D. 2 11/16.

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The probability of it snowing in Eastern Canada tomorrow is 0.4. The probability of it snowing in Western Canada tomorrow is 2/5

Viktor [21]

Answer:

Neither

Step-by-step explanation:

They both have the same probability because 2/5 and 0.4 have the same value.

6 0

3 years ago

Jon is 3 years younger than Laura. The product of their ages is 1,330. If j represents johns age and j+3 represents Laura’s age,

Lyrx [107]

645668888888854389000099876543322247

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3 years ago

Chelsey wants to join a fitness club. The fitness club charges an initial membership fee of $55 and a monthly fee of $19.50. She

Kay [80]

So if you have to pay 55 out front and then continue to pay 19.50 monthly the equation will look like this:
19.50*m + 55 = x
(M stands for month)
She has 250 dollars to spend so add that in for x
<span>19.50*m + 55 = 250.
Use inverse operations.
250-55 and 55-55
19.50*m = 195
195/19.50 and 19.50/19,50
m=10
Your answer is 10</span>

4 0

3 years ago

Solve y" + y = tet, y(0) = 0, y'(0) = 0 using Laplace transforms.

irina1246 [14]

Answer:

The solution of the diferential equation is:

$y(t)=\frac{1}{2}cos(t)- \frac{1}{2}e^{t}+\frac{t}{2} e^{t}$

Step-by-step explanation:

Given $y" + y = te^{t}$ ; y(0) = 0 ; y'(0) = 0

We need to use the Laplace transform to solve it.

ℒ[y" + y]=ℒ[ $te^{t}$ ]

ℒ[y"]+ℒ[y]=ℒ[ $te^{t}$ ]

By using the Table of Laplace Transform we get:

ℒ[y"]=s²·ℒ[y]+s·y(0)-y'(0)=s²·Y(s)

ℒ[y]=Y(s)

ℒ[ $te^{t}$ ]= $\frac{1}{(s-1)^{2}}$

So, the transformation is equal to:

s²·Y(s)+Y(s)= $\frac{1}{(s-1)^{2}}$

(s²+1)·Y(s)= $\frac{1}{(s-1)^{2}}$

Y(s)= $\frac{1}{(s^{2}+1)(s-1)^{2}}$

To be able to separate in terms, we use the partial fraction method:

$\frac{1}{(s^{2}+1)(s-1)^{2}}=\frac{As+B}{s^{2}+1} +\frac{C}{s-1}+\frac{D}{(s-1)^2}$

1=(As+B)(s-1)² + C(s-1)(s²+1)+ D(s²+1)

The equation is reduced to:

1=s³(A+C)+s²(B-2A-C+D)+s(A-2B+C)+(B+D-C)

With the previous equation we can make an equation system of 4 variables.

The system is given by:

A+C=0

B-2A-C+D=0

A-2B+C=0

B+D-C=1

The solution of the system is:

A=1/2 ; B=0 ; C=-1/2 ; D=1/2

Therefore, Y(s) is equal to:

Y(s)= $\frac{s}{2(s^{2} +1)} -\frac{1}{2(s-1)} +\frac{1}{2(s-1)^{2}}$

By using the inverse of the Laplace transform:

ℒ⁻¹[Y(s)]=ℒ⁻¹[ $\frac{s}{2(s^{2} +1)}$ ]-ℒ⁻¹[ $\frac{1}{2(s-1)}$ ]+ℒ⁻¹[ $\frac{1}{2(s-1)^{2}}$ ]

$y(t)=\frac{1}{2}cos(t)- \frac{1}{2}e^{t}+\frac{t}{2} e^{t}$

8 0

3 years ago

a university has raised $8,000 for a new scholarship fund. A university trustee offers to match the donation up 60% if the unive

Stels [109]

Well if they match 60% of the $8,000 then it will be $14,300 but if they match 60% of the 8,000+1,500 then it would be $15,200.

Hope this helps

~Nayiah~

7 0

3 years ago

Read 2 more answers