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adell [148]
3 years ago
8

A chef prepared five chocolate tortes for a dinner party. The guests consumed 2 5/16 tortes. How many

Mathematics
2 answers:
Pavlova-9 [17]3 years ago
8 0
5 - 2\frac{5}{16} = \frac{80}{16} - \frac{37}{16} = \frac{43}{16}\\\\=\boxed{\bf{2\frac{11}{16}}}

Your final answer is D. 2 ¹¹/₁₆.
Alenkinab [10]3 years ago
3 0
If you would like to know how many tortes are left, you can calculate this using the following steps:

five chocolate tortes - 2 5/16 tortes = 5 - 2 5/16 = 5 - 37/16 =  80/16 - 37/16 = 43/16 = 2 11/16

The correct result would be D. 2 11/16.
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We are given the equations 3x+5y=-3 and x-5y=-5.

Both equations have a 5y  term which allows us to easily solve the system by elimination. To do so we will add the equations together like a simple addition problem by adding the x terms together, the y terms together, and the integer answers together.

3x + 5y = -3
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