The Correct Answer is B
B.False
Answer:
AH = 1 or 4
CH = 4 or 1
Step-by-step explanation:
An altitude divides a right triangle into similar triangles. That means the sides are in proportion, so ...
AH/BH = BH/CH
AH·CH = BH²
The problem statement tells us AH + CH = AC = 5, so we can write
AH·(5 -AH) = BH²
AH·(5 -AH) = 2² = 4
This gives us the quadratic ...
AH² -5AH +4 = 0 . . . . in standard form
(AH -4)(AH -1) = 0 . . . . factored
This equation has solutions AH = 1 or 4, the values of AH that make the factors be zero. Then CH = 5-AH = 4 or 1.
33 ÷ 3
----------- = 11 / 12.
36 ÷ 3
It's simplest form is 11 / 12.
Hi there! A = 78
A + 44 = B
We can plug in the values of A and B into the equation. We then get an equation with only one variable (x), which we can solve.
1x + 76 + 44 = - 6x + 134
Collect terms.
1x + 120 = - 6x + 134
Add 6x to both sides.
7x + 120 = 134
Subtract 120 from both sides
7x = 14
Divide both sides by 7
x = 14 / 7 = 2
A = 1x + 76
Now plug in the value of x we just found
A = 2 + 76 = 78