Answer:
y= 10/3 x -18
Step-by-step explanation:
Perpendicular lines meet the following condition:
m2*m1=-1 (1)
The product of their slope is -1.
From the equation of the first line we can obtain the first slope.
y=-0.3x+6 -> m1=-0.3
Hence, the slope of our desired line is obtained from equation (1).
m2=10/3.
Remember, the equation of a line is given by:
y=mx+b
Now, we need to find the term 'b' and we will do that by evaluating the point (3,-8).
-8=10/3 * 3 +b.
b=-18.
Finally, our desired line has the following equation:
y= 10/3 x -18
Answer:
The diagonals of the square JKLM are perpendicular to each other since
.
Step-by-step explanation:
Let JL and KM the diagonals of the square JKLM, if JL and KM are perpendicular to each other, then
. First, we determine the value of each vector:
(1)
![\overrightarrow{JL} = (4,4)-(0,0)](https://tex.z-dn.net/?f=%5Coverrightarrow%7BJL%7D%20%3D%20%284%2C4%29-%280%2C0%29)
![\overrightarrow{JL} = (4,4)](https://tex.z-dn.net/?f=%5Coverrightarrow%7BJL%7D%20%3D%20%284%2C4%29)
(2)
![\overrightarrow{KM} = (0,4)-(4,0)](https://tex.z-dn.net/?f=%5Coverrightarrow%7BKM%7D%20%3D%20%280%2C4%29-%284%2C0%29)
![\overrightarrow{KM} = (-4,4)](https://tex.z-dn.net/?f=%5Coverrightarrow%7BKM%7D%20%3D%20%28-4%2C4%29)
Then,
![(4, 4)\,\bullet\,(-4,4) = -16+16 = 0](https://tex.z-dn.net/?f=%284%2C%204%29%5C%2C%5Cbullet%5C%2C%28-4%2C4%29%20%3D%20-16%2B16%20%3D%200)
Therefore, the diagonals of the square JKLM are perpendicular to each other.
Answer:
110.00
Step-by-step explanation:
Take the thousands place and round up with 10. In turn that will get the hundredths place to 10 to and make the tenths place to a 10 too and so on with the ones place until you end up with 110.00
Cracked:all=3:4
3/4=x/28
cross multiply or times both sides by 28
3*7=x
21=x
21 are cracked (bad deal)
If f(x) = x - 2, then f(-3) = -5