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adoni [48]
2 years ago
15

What is an equivalent expression of 28p^9q^-5/12p^-6q^7

Mathematics
1 answer:
Marta_Voda [28]2 years ago
5 0

B. 7p^{15} /3q^{12}

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Pleasssseeeee hhhheeeellllppppp
Margarita [4]

Answer:

They look similar but just rotated

Step-by-step explanation:

pls mark as brainliest

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3 years ago
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 Ill Mark Brainliest if you answer correctly. The figure below shows a shaded circular region inside a larger circle:
pogonyaev

First we have to find the areas of both circle using the formula

Area = \pi r^2

For larger circle,

Area=  \pi(5)^2 = 25 \pi

For smaller circle,

Area = \pi (4)^2 = 16 \pi

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8 0
3 years ago
Subject: Pre-algebra
charle [14.2K]

Answer:

1: true

2: false

Step-by-step explanation:

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2 years ago
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When working with the square root of a number, when would you have only a positive answer and when would you have both a positiv
Rama09 [41]
<span>Lets make it clear: You would have a positive answer when the value you are looking for has to be a positive number. On the other hand you would have a positive and a negative answer when you take the square root of something that doesn't have to be positive. it could be either because when a negative number is squared it becomes positive and when a positive number is squared it stays positive as well.</span>
8 0
3 years ago
Please help, need for math hw and cant figure it out
swat32

The standard form of the quadratic function f(x) = -3x^2 + 6x - 2 is f(x) = -3x^2 + 6x - 2

<h3>How to represent the quadratic function in standard form?</h3>

The quadratic function is given as

f(x) = -3x^2 + 6x - 2

The standard form of a quadratic function is represented as:

f(x) = ax^2 + bx + c

When both equations are compared, we can see that the function f(x) = -3x^2 + 6x - 2 is already in standard form

Where

a = -3

b = 6

c = -2

Hence, the standard form of the quadratic function f(x) = -3x^2 + 6x - 2 is f(x) = -3x^2 + 6x - 2

Read more about quadratic function at

brainly.com/question/25841119

#SPJ1

7 0
1 year ago
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