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3 years ago

Whats the answer??????

Mathematics

2 answers:

Temka [501]3 years ago

7 0

4/1 x 3/2 = 12/2
6/9 x 1/7 = 6/63
5/6 x 2/1 = 10/6
8/3 x 1/6 = 8/18
8/1 x 5/8 = 40/8

garik1379 [7]3 years ago

5 0

Answer:

4 divided by 2/3 = 6

6/9 divided by 7 = 6/63 - 2/21

5/6 divided by 1/2 = 10 / 6 - 1 4/6

2 2/3 divided by 6 = 8/18 - 4/9

8 divided by 1 3/5 = 40/8 = 5

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When a group of colleagues discussed where their annual retreat should take place, they found that all the colleagues: 25 would

raketka [301]

Answer:

63 people

Step-by-step explanation:

We have the following:

Let P: the subset of those 25 who would not go to a park

Let B: the subset of those 27 who would not go to the beach

Let C: the subset of those 24 that would not go to a cottage

Thus:

The intersection PB of subsets P and B consists of 10 people (i.e. neither a park nor a beach)

The intersection BC of subsets B and C consists of 7 people (i.e. neither beach nor cottage)

The intersection PC of subsets P and C consists of 6 people (i.e. neither a park nor a cottage)

We are also told that the PBC intersection of subsets P, B, and C consists of 4 person (i.e. would not go to a park, beach, or cottage)

The complement of the union of the sets P, B and C for the whole group consists of 6 people (that is, willing to go to the three places)

The formula to apply is as follows:

# (PUBUC) = #A + #B + #C - #AnB - #BnC - #AnC + #AnBnC

Replacing:

= 25 + 27 + 24 - 10 - 7 - 6 + 4

= 57 people

those who are willing to all who are 6 would be missing us, therefore:

57 + 6 = 63

The group consists of a total of 63 people.

8 0

3 years ago

PLEASE HELP ASAP PLEASE PLEASE PLEASE

vovikov84 [41]

Answer:

First blank- 4x

Second blank- combine

Third blank- X

Hope this helps :3

(Write feedback if incorrect)

6 0

3 years ago

6(2x²-5) = [?]<br> x = -3

Korvikt [17]

Answer:

Step-by-step explanation:

plug in -3 as x

6(2(-3)^2-5)

6(2(9)-5)

6(18-5)

6(13)

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2 years ago

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Find the prime factorization of 50 using exponents

Elden [556K]

Five squared with the little two and 2 because 5 Times 10 is 50 and five is prime so then from 10 and you get five and two and both five and two are prime

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3 years ago

A biology test is worth 100 points and has 36 questions.

Ad libitum [116K]

Answer:

(a) 7 essays and 29 multiple questions

(b) Your friend is incorrect

Step-by-step explanation:

Represent multiple choice with M and essay with E.

So:

$M + E= 36$ --- Number of questions

$2M + 6E = 100$ --- Points

Solving (a): Number of question of each type.

Make E the subject of formula in $M + E= 36$

$E = 36 - M$

Substitute 36 - M for E in $2M + 6E = 100$

$2M + 6(36 - M) = 100$

$2M + 216 - 6M = 100$

Collect Like Terms

$2M - 6M = 100 - 216$

$-4M = - 116$

Divide both sides by -4

$M = \frac{-116}{-4}$

$M = 29$

Substitute 29 for M in $E = 36 - M$

$E = 36 - 29$

$E = 7$

Solving (b): Can the multiple questions worth 4 points each?

It is not possible.

See explanation.

If multiple question worth 4 points each, then

$2M + 6E = 100$ would be:

$4M + xE = 100$

Where x represents the number of points for essay questions.

Substitute 7 for E and 29 for M.

$4 * 29 + x * 7 = 100$

$116 + 7x = 100$

Subtract 116 from both sides

$116-116 + 7x = 100 -116$

$7x = 100-116$

$7x = -16$

Make x the subject

$x = -\frac{16}{7}$

Since the essay question can not have worth negative points.

Then, it is impossible to have the multiple questions worth 4 points

<em>Your friend is incorrect.</em>

6 0

3 years ago