Answer:
- $8000 at 1%
- $2000 at 10%
Step-by-step explanation:
It often works well to let a variable represent the amount invested at the higher rate. Then an equation can be written relating amounts invested to the total interest earned.
__
<h3>setup</h3>
Let x represent the amount invested at 10%. Then 10000-x is the amount invested at 1%. The total interest earned is ...
0.10x +0.01(10000 -x) = 280
<h3>solution</h3>
Simplifying gives ...
0.09x +100 = 280
0.09x = 180 . . . . . . . subtract 100
x = 2000 . . . . . . divide by 0.09
10000 -x = 8000 . . . . amount invested at 1%
<h3>1.</h3>
$8000 should be invested in the 1% account
<h3>2.</h3>
$2000 should be invested in the 10% account
Answer:
.4 x .9
Step-by-step explanation:
I believe that b.Fractions are rational numbers is not true
sorry if its wrong
3x+2y=50
x+y=19
x=12, y=7
12 jumps, 7 "raise the roof"s
Answer:
UW ≈ 6.55 ≈ 7
Step-by-step explanation:
cos (35) = adjacent/hypotenuse
cos(35) = UW/VW
cos(35) = UW/8
8*cos(35) = UW
UW ≈ 6.55
Hope this helped! <3