The answer to this question is b
Answer:
4 cm
Step-by-step explanation:
The equation of a parabola with its vertex at the origin can be written as ...
y = 1/(4p)x^2
The problem statement tells us that one point on the parabola is (x, y) = (12, 9). We can put these values into the equation and solve for p, the distance from the focus to the vertex.
9 = 1/(4p)(12^2)
9×4/144 = 1/p = 1/4 . . . . . . . . multiply by the inverse of the coefficient of 1/p
Then p = 4, and the bulb is 4 cm from the vertex.
Okay lets start with "what is a kite?" A kite is a shape which has 4 sides of which 2 pairs of two sides are equal and the center angle is 90 degrees. So mark up your drawing with tick marks to show that segment DF and segment FG are equal (just put a little tick mark on those segments). Similarly segments DH and GH are equal so put two tick marks on them to show they are equal. Mark the center angle with a little square to show it is 90 degrees. Let me give you some hints on the answers. a. is given like you have b. is what you marked on your drawing and is the definition of a kite e. is definition of congruency or even substitution f. Reflexive property - remember it just says that something is congruent to itself. g. looks like the HL property h. you can say that because of CPCTC.
Y = xe^x
dy/dx(e^x x)=>use the product rule, d/dx(u v) = v*(du)/(dx)+u*(dv)/(dx), where u = e^x and v = x:
= e^x (d/dx(x))+x (d/dx(e^x))
y' = e^x x+ e^x
y'(0) = 1 => slope of the tangent
slope of the normal = -1
y - 0 = -1(x - 0)
y = -x => normal at origin
The time it will take the roller coaster to reach the ground is 171.65 seconds
<h3>Function and values</h3>
Given the roller coaster’s height given by the following parameters
h = –0.025t² + 4t + 50
On the ground level, the height will be zero. Substitute h = 0 and determine the value of t
–0.025t² + 4t + 50 = 0
0.025t² - 4t - 50 = 0
Factorize
On factorizing the time it will take the roller coaster to reach the ground is 171.65 seconds
Learn more on functions here: brainly.com/question/10439235
#SPJ1
