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Marizza181 [45]
2 years ago
9

What is the volume of a cylindrical bucket that is 35 cm tall and has a base with a diameter of 21 cm? Use pi= 22/7 and round yo

ur answer to the nearest tenth of a cubic centimeter.
Mathematics
2 answers:
Romashka [77]2 years ago
7 0

Answer:

the answer is 12127.5cm³

Step-by-step explanation:

Natali [406]2 years ago
6 0
The volume of a cylinder is given by the multiplication of the area of the base by the height of the cylinder.  π×r²(area of the base) × h (height of the cylinder) ⇔
\frac{22}{7}×(\frac{21}{2} )^{2}cm²×35cm=12127.5cm³
(r is half of the diameter. Because we are doing the square of r, the cm also are squared.)
Rounding to the nearest tenth is to round the result so that it maintains a number after the point - the result is 12127.5cm³
You might be interested in
Rectangle PQRS is rotated 90 counterclockwise about the origin what are the coordinates of point Q
inna [77]
You have not provided the diagram/coordinates for point Q, therefore, I cannot provide an exact answer.
However, I can help you with the concept.

When rotating a point 90° counter clock-wise, the following happens:
coordinates of the original point: (x,y)
coordinates of the image point: (-y,x)

Examples:
point (2,5) when rotated 90° counter clock-wise, the coordinates of the image would be (-5,2)

point (1,9) when rotated 90° counter clock-wise, the coordinates of the image would be (-9,1)

point (7,4) when rotated 90° counter clock-wise, the coordinates of the image would be (-4,7)

Therefore, for the given point Q, all you have to do to get the coordinates of the image is apply the transformation:
(x,y) .............> are changed into.............> (-y,x)

Hope this helps :)
5 0
2 years ago
Read 2 more answers
Help with this please i have a few minutes left!!!!
lara [203]
Answer: 5.44449

step-by-step explanation:
5 0
3 years ago
Before changes to its management staff, an automobile assembly line operation had a scheduled mean completion time of minutes. T
Sergio [31]

No, we don't have evidence to support that the mean completion time under new management has decreased but we can conclude that it remains at 15.5 minutes.

Given mean of 15.5 minutes , standard deviation of 1.7 minutes, sample size of 90 and sample mean of 15.4 minutes.

We can do the following study for conclusion:

Firstly the null hypothesis is

H_{0}: x=15.5

The alternate hypothesis is

H_{1}: x < 15.5

since the value is less than this is a one tailed test.

Z=x bar-x/d/\sqrt{n}

where x is sample mean and d is standard deviation.

Z=15.4-15.5/1.7/\sqrt{90}

=-0.1/1.7/9.4868

=-0.560

Critical value of Z at 0.1 level of significance

Z=-1.28

We fails to reject the null hypothesis since -0.560>-1,28

Hence we don't have evidence to support that the mean completion time under new management has decreased but we can conclude that it remains at 15.5 minutes.

Learn more about hypothesis at brainly.com/question/11555274

#SPJ4

Question is incomplete. It should include:

mean of 15.5 minutes ,

standard deviation of 1.7 minutes,

sample size of 90

and sample mean of 15.4 minutes.

5 0
1 year ago
Muhammad owns 8 fewer swim suits than Charlie. Let k represent the number of Charlie's swim suits. Identify the expression that
andre [41]

Answer:

Number of Muhammad's swim suits = k - 8

Step-by-step explanation:

Given:

Number of Charlie's swim suits = K

Number of Muhammad's swim suits = 8 less than Charlie

Find:

Expression [Number of Muhammad's swim suits]

Computation:

Number of Muhammad's swim suits = 8 less than Charlie

Number of Muhammad's swim suits = k - 8

6 0
2 years ago
What is the inverse of cube root x/3 +1
Ostrovityanka [42]

Answer:

{f}^{ - 1} (x) = 3 {x}^{2}  - 3

Step-by-step explanation:

We want to find the inverse of

y = \sqrt[3]{ \frac{x}{3} + 1}

We interchange x and y to get:

x= \sqrt[3]{ \frac{y}{3} + 1}

We solve for y;

{x}^{2}  =  \frac{y}{3}  + 1

Multiply through by 3

3 {x}^{2}  = y + 3

Subtract 1 from both sides:

y = 3 {x}^{2}  - 3

Therefore the inverse is

{f}^{ - 1} (x) = 3 {x}^{2}  - 3

8 0
3 years ago
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