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3 years ago

The area of one rectangle is twice the area of another. What is the ratio of their perimeters

Mathematics

1 answer:

Veronika [31]3 years ago

6 0

Answer:

The answer is 8 units! Hope this helps!

Step-by-step explanation:f the length of any one side of the square is x, then the area is x2, and the perimeter is 4x. If the area is twice the perimeter, x2 = 2(4x), and x2 − 8x= 0. By factoring, we see this equation is equivalent to x(x − 8) = 0, which has solutions 0 and 8. The length cannot be 0, so it must be 8 units.

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Write an equivalent expression for (2m+3)(m-1).

KonstantinChe [14]

You can do the box method, multiply them. Then combine like terms.
You can also use the foil method.

8 0

3 years ago

The perimeter of a triangle is 7 m. The longest side is twice the length of the shortest side. The sum of the

34kurt

Answer:

See below in bold.

Step-by-step explanation:

Let the length of the shortest side be x, then the longest side = 2x.

Also x + y = 2x + 1 where y = length of the middle side,

Simplifying:

2x - x - y = -1

x - y = -1 (A)

Also as the perimeter = 7:

x + 2x + y = 7

3x + y = 7 (B)

Adding (A) and (B):

4x + 0 = 6

x = 6/4 = 1.5

Plug x = 1.5 into equation B:

3(1.5) + y = 7

y = 7 - 4.5 = 2.5.

Answer:

So the shortest side = 1.5, middle = 2.5 and longest = 2*1.5 = 3.

3 0

2 years ago

What is this figure?

Wewaii [24]

Answer:

parallelogram, quadralateral, and rhombus

Step-by-step explanation:

8 0

3 years ago

What percent of 72 is 48 with step by step process

Sedaia [141]

Answer:

67%

Step-by-step explanation:

There are a few methods to finding the percent of a number. You can use proportions:

$\frac{percent}{100}=\frac{48}{72}$

The 'percent' is the percent of the fraction that you are looking for, or 48/72.

Cross-multiply: 72x = (48)(100) or 72x = 4800

Divide both sides by 72: 72x/72 = 4800/72

Solve for 'x': x = 66.6666...

Round 66.666.... to the nearest percent: 67%

8 0

3 years ago

Farmer Jones, and his wife, Dr. Jones, decide to build a fence in their field, to keep the sheep safe. Since Dr. Jones is a math

alex41 [277]

Answer: $\frac{8}{3}\times \sqrt{\frac{2}{5}}$

Step-by-step explanation:

Given two upward facing parabolas with equations

$y=6x^2 & y=x^2+2$

The two intersect at

$6x^2=x^2+2$

$5x^2=2$

$x^2$ = $\frac{2}{5}$

x= $\pm \sqrt{\frac{2}{5}}$

area enclosed by them is given by

A= $\int_{-\sqrt{\frac{2}{5}}}^{\sqrt{\frac{2}{5}}}\left [ \left ( x^2+2\right )-\left ( 6x^2\right ) \right ]dx$

A= $\int_{\sqrt{-\frac{2}{5}}}^{\sqrt{\frac{2}{5}}}\left ( 2-5x^2\right )dx$

A= $4\left [ \sqrt{\frac{2}{5}} \right ]-\frac{5}{3}\left [ \left ( \frac{2}{5}\right )^\frac{3}{2}-\left ( -\frac{2}{5}\right )^\frac{3}{2} \right ]$

A= $\frac{8}{3}\times \sqrt{\frac{2}{5}}$

7 0

3 years ago