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Vladimir79 [104]
3 years ago
5

Add parentheses to solve the equation 16+3*4-2+5=21

Mathematics
1 answer:
Shalnov [3]3 years ago
5 0

Answer:4

Step-by-step explanation:

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Fittoniya [83]

\qquad\qquad\huge\underline{{\sf Answer}}♨

Here we go ~

According to given figure,

\qquad \sf  \dashrightarrow \:x + 68 = 174

\qquad \sf  \dashrightarrow \:x = 174 - 68

\qquad \sf  \dashrightarrow \:x = 106 \degree

3 0
2 years ago
Jeremiah just got hired for a new job and will make $35,000 in his first year. Jeremiah was told that he can expect to get raise
trasher [3.6K]

Answer:

Jeremiah make $66,500 in his 9th year

Step-by-step explanation:

3,500*9=31,500

35,000+31,500=66,500

5 0
3 years ago
Marco wants to use the distributive property to find the value of 17 • 69 + 17 • 31. Which expression can he use?
natulia [17]

As per the problem,

Marco wants to use the distributive property to find the value of 17 • 69 + 17 • 31.

We have been asked to find , which expression can be used?

As per the distributive property , we know that

a(b+c)=a.b+a.c

Now apply this on the given expression we get

17. 69 + 17 .31=17(69+31)

Hence the expression , which can be used is 17(69+31)

6 0
3 years ago
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6 0
4 years ago
The desired percentage of SiO2 in a certain type of aluminous cement is 5.5. To test whether the true average percentage is 5.5
miskamm [114]

Answer:  

z=-3.25

p_v =2*P(z  

Step-by-step explanation:  

1) Data given and notation  

\bar X=5.24 represent the mean production for the sample  

\sigma=0.32 represent the sample standard deviation for the sample  

n=16 sample size  

\mu_o =5.5 represent the value that we want to test  

\alph=0.05a represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

Part a: State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean production is different from 5.5 tons, the system of hypothesis would be:  

Null hypothesis:\mu =5.5  

Alternative hypothesis:\mu \neq 5.5  

If we analyze the info given we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{5.24-5.5}{\frac{0.32}{\sqrt{16}}}=-3.25  

P-value

Since this is a two side test the p value would be:  

p_v =2*P(z  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the production its significant different compared to the desired percentage of SiO2 of 5.5 at 5% of signficance.  

7 0
3 years ago
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