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3 years ago

I need the answer to number 4 plz

Mathematics

1 answer:

artcher [175]3 years ago

6 0

Answer:

equation of that line: y=-1

coordinate of that point(-1,-1)

a, only 5,6 >4 , then P = 2/6 =1/3 =33.33%

b, 1,3,5 are odd, then P = 3/6 =1/2 =50%

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Please help Write the decimal as a fraction in lowest terms: -2.013

svetlana [45]

Answer:

-2 13/1000

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Kate, Alexia, and Trina just completed the 400-meter dash at the track meet. Kate finished the race 6 seconds faster than Alexia

Digiron [165]

Answer:

Kate = 52 seconds, Alexia = 58 seconds, Trina = 49 seconds

Step-by-step explanation:

A = K + 6

T = K - 3

K + A + T = 2 min 39 sec or 159 sec

K + (K + 6) + (K - 3) = 159sec

3K + 3 = 159sec

3K = 156sec

K = 52 sec

A = 52 + 6 = 58 sec

T = 52 - 3 = 49 sec

8 0

3 years ago

Using appropriate properties, find the value of 249² - 248²

Lady_Fox [76]

Answer:

$\boxed{\bold{\huge{\boxed{497}}}}$

Step-by-step explanation:

=> $\sf 249^2 - 248^2$

Using Formula $\sf a^2 - b^2 = (a+b)(a-b)$

Where

a = 249

b = 248

=> $\sf (249+248)(249-248)$

=> $\sf (497)(1)$

=> 497

3 0

3 years ago

If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar

Oksana_A [137]

Answer:

$n + 4 {n \choose 2} + 6 {n \choose 3} + 4 {n \choose 4} + {n \choose 5}$

Step-by-step explanation:

Lets divide it in cases, then sum everything

Case (1): All 5 numbers are different

In this case, the problem is reduced to count the number of subsets of cardinality 5 from a set of cardinality n. The order doesnt matter because once we have two different sets, we can order them descendently, and we obtain two different 5-tuples in decreasing order.

The total cardinality of this case therefore is the Combinatorial number of n with 5, in other words, the total amount of possibilities to pick 5 elements from a set of n.

${n \choose 5 } = \frac{n!}{5!(n-5)!}$

Case (2): 4 numbers are different

We start this case similarly to the previous one, we count how many subsets of 4 elements we can form from a set of n elements. The answer is the combinatorial number of n with 4 ${n \choose 4} .$

We still have to localize the other element, that forcibly, is one of the four chosen. Therefore, the total amount of possibilities for this case is multiplied by those 4 options.

The total cardinality of this case is $4 * {n \choose 4} .$

Case (3): 3 numbers are different

As we did before, we pick 3 elements from a set of n. The amount of possibilities is ${n \choose 3} .$

Then, we need to define the other 2 numbers. They can be the same number, in which case we have 3 possibilities, or they can be 2 different ones, in which case we have ${3 \choose 2 } = 3$ possibilities. Therefore, we have a total of 6 possibilities to define the other 2 numbers. That multiplies by 6 the total of cases for this part, giving a total of $6 * {n \choose 3}$

Case (4): 2 numbers are different

We pick 2 numbers from a set of n, with a total of ${n \choose 2}$ possibilities. We have 4 options to define the other 3 numbers, they can all three of them be equal to the biggest number, there can be 2 equal to the biggest number and 1 to the smallest one, there can be 1 equal to the biggest number and 2 to the smallest one, and they can all three of them be equal to the smallest number.

The total amount of possibilities for this case is

$4 * {n \choose 2}$

Case (5): All numbers are the same

This is easy, he have as many possibilities as numbers the set has. In other words, n

Conclussion

By summing over all 5 cases, the total amount of possibilities to form 5-tuples of integers from 1 through n is

$n + 4 {n \choose 2} + 6 {n \choose 3} + 4 {n \choose 4} + {n \choose 5}$

I hope that works for you!

4 0

3 years ago

What is the equation of the following line? Be sure to scroll down first to see all answer options.

Annette [7]

From the figure the given line passes through the points (0, 0) and (-4, 8).

Recall that the equation of a straight line is given by
$\frac{y-y_1}{x-x_1} = \frac{y_2-y_1}{x_2-x_1}$

Thus, The equation of the given figure is given by
$\frac{y-0}{x-0} = \frac{8-0}{-4-0}= \frac{8}{-4} \\ \\ -4y=8x \\ \\ y=-2x$

8 0

3 years ago