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3 years ago

Jeremy and his friends ate 5/8 of a pie. if the pie was cut into eight pieces, how much pie is left over?

Mathematics

1 answer:

Bas_tet [7]3 years ago

5 0

Simply do 8/8 - 5/8
Your answer: 3/8 of the pie is left

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Find the measures of the angles in the figure.

Vinvika [58]

Answer:

$120^o,\,120^o,\,60^o,\,\,\,and\,\,\,60^o$

which agrees with the first answer in the list of possible options.

Step-by-step explanation:

We can use the fact that the addition of all four internal angles of a quadrilateral must render $360^o$ . Then we can create the following equation and solve for the unknown "h":

$2h+2h+h+h = 360^o\\6h=360^o\\h=60^o$

Therefore the angles of this quadrilateral are:

$120^o,\,120^o,\,60^o,\,\,\,and\,\,\,60^o$

3 0

3 years ago

Read 2 more answers

PLEASE ITS NOT THAT HARD

nevsk [136]

Answer:

25. 0.0036 26. 1/64

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

compute the projection of → a onto → b and the vector component of → a orthogonal to → b . give exact answers.

Nina [5.8K]

$\text { Saclar projection } \frac{1}{\sqrt{3}} \text { and Vector projection } \frac{1}{3}(\hat{i}+\hat{j}+\hat{k})$

We have been given two vectors $\vec{a}$ and $\vec{b}$ , we are to find out the scalar and vector projection of $\vec{b}$ onto $\vec{a}$

we have $\vec{a}=\hat{i}+\hat{j}+\hat{k}$ and $\vec{b}=\hat{i}-\hat{j}+\hat{k}$

The scalar projection of $\vec{b}$ onto $\vec{a}$ means the magnitude of the resolved component of $\vec{b}$ the direction of $\vec{a}$ and is given by

The scalar projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|}$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\sqrt{1^2+1^1+1^2}} \\&=\frac{1^2-1^2+1^2}{\sqrt{3}}=\frac{1}{\sqrt{3}}\end{aligned}$

The Vector projection of $\vec{b}$ onto $\vec{a}$ means the resolved component of $\vec{b}$ in the direction of $\vec{a}$ and is given by

The vector projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|^2} \cdot(\hat{i}+\hat{j}+\hat{k})$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\left(\sqrt{1^2+1^1+1^2}\right)^2} \cdot(\hat{i}+\hat{j}+\hat{k}) \\&=\frac{1^2-1^2+1^2}{3} \cdot(\hat{i}+\hat{j}+\hat{k})=\frac{1}{3}(\hat{i}+\hat{j}+\hat{k})\end{aligned}$

To learn more about scalar and vector projection visit:brainly.com/question/21925479

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3 0

1 year ago

Simplify:<br> 6x-7-11x+x<br><br> show all work if possible

Lady_Fox [76]

Just matter of combining like terms
6x - 7 - 11x + x =
(6x + x - 11x) - 7 =
(7x - 11x) - 7 =
- 4x - 7 <===

3 0

3 years ago

Graph a line with a slope of - 3/4 that contains the point (2 3)

Savatey [412]

Answer:

Step-by-step explanation:

1. Graph point (2, 3)

2. Go down 3, 4 to the right or up 3 and 4 to the left

3. Repeat until you have about 3 to 4 points

4. Create a line

6 0

3 years ago