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kipiarov [429]
3 years ago
9

What is the slope-intercept form of this equation?

Mathematics
1 answer:
kirill [66]3 years ago
5 0

Answer:

y = -8x + 12

Step-by-step explanation:

Slope intercept form: y = mx + b

m ---> Slope   & b ----> y-intercept

8x + y = 12

Subtract 8x from both sides

y = -8x + 12

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Given a≠±b and a^2−b^2 / a+b =12, find a−b.<br> pls hlep
Readme [11.4K]

Answer:

a - b = 12

Step-by-step explanation:

Given

\frac{a^2-b^2}{a+b} = 12 ← factor the numerator

a² - b² ← is a difference of squares and factors as

a² - b² = (a - b)(a + b)

Thus

\frac{(a-b)(a+b)}{a+b} = 12

Cancel the common factor (a + b) on numerator/ denominator, thus

a - b = 12

7 0
3 years ago
Hi, I need to send you a screenshot​
Kazeer [188]
Whyyy notttt I guessss
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3 years ago
18. A secretary works a 40-hour week and is paid a basic rate of $22.50 per hour.
tensa zangetsu [6.8K]
40 hours at $22.50 is $900. The additional 12 hours at $33.75 is $405.
900+405= 1305 so the secretary’s total wage is $1305
8 0
3 years ago
Help me please been stuck for an hour
rewona [7]

Answer:

29/28

Step-by-step explanation:

-  \frac{2}{7}  \times ( - 3 \frac{5}{8} ) \\  -  \frac{2}{7}  \times ( -  \frac{29}{8} ) \\

=  \frac{29}{28}

4 0
3 years ago
Can somebody please walked through this, I'm so confused and I have a test in 6 hours...
erastova [34]

Answer:

Q3: x = 4, y = 4, z = 4

Q4: x = 6, y = 0, z = -4

Step-by-step explanation:

Question 3: Simultaneous equations requires us to solve for x, y and z.

Since all three equations have a z in them, I will first solve for z.

Substitute in the first and third equation into the second equation.

First equation: x = 5z - 16

Second Equation: -4x + 4y - 5z = -20

Third equation: y = -z + 8

Substituting in x = 5z - 16 and y = -z + 8 for the x and y in the second equation.

-4(5z - 16) + 4(-z + 8) - 5z = -20

Expand

-20z + 64   - 4z + 32   - 5z = -20

Simplify and solve for z by putting all the numbers on one side and all the z's on the other side of the equals

-20z - 4z - 5z = -20 - 32 - 64

-29z = -116

z = -116/-29

z = 4

Substitute in this z value into the first and last equation and then solve for x and y

x = 5z - 16

x = 5(4) - 16

x = 20 - 16

x = 4

And

y = -z + 8

y = -(4) + 8

y = 4 (Its just a coincidence that they all equal to 4, I promise)

Question 5: A little bit harder of a question. Since the first and second equation both only have y and z, we can solve it using the elimination method.

Rearrange them so that the letters are on one side and numbers on the other side.

First equation: y + 6z = -24

Second equation: z + 2y = -4

I will choose to eliminate the y (You can choose either or)

Multiply the first equation by 2

2(y + 6z = -24)

2y + 12z = -48

Now that 2y is in both equations, we can minus one equation from the other to eliminate the y (I will minus the second from the first)

First Eq: 2y + 12z = -48

Second Eq: z + 2y = -4

2y - 2y = 0y

12z - z = 11z

-48 - (-4) = -44

Type these answers into a new equation

0y + 11z = - 44

Since y is 0, ignore it. Solve for z

11z = -44

z = -44/11

z = - 4

Substitute our z into either the first or second equation and solve for y (It doesnt matter which one you choose, I just did the second equation)

z + 2y = -4

(-4) + 2y = -4

2y = -4 + 4

2y = 0

y = 0

Substitute in our y and z values into the third equation and solve for x

-6x - 6y - 6z = -12

-6x - 6(0) - 6(-4) = -12

-6x - 0 + 24 = -12

-6x = -12 - 24

-6x = -36

x = -36/-6

x = 6

6 0
3 years ago
Read 2 more answers
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