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3 years ago

Solve the equation. x2 = 160

Mathematics

2 answers:

UNO [17]3 years ago

8 0

zhannawk [14.2K]3 years ago

7 0

80 because 160 divided by 2 is 80 so 2 x 80

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What’s the square root of 108 a to the 7th power b to the 5th power

MissTica

Answer:

Step-by-step explanation:

Factor all the factors making up the square root.

108: 2*2*3*3*3

a^7: a*a*a*a*a*a*a

b^5:b * b * b * b * b

The rule for taking a square root of this is

For every pair, you get to take one number outside the root sign and throw the other one away.

2*3*a * a * a* b * b√(3*a * b)

6a^3b^2 * √(3*a*b)

4 0

3 years ago

Brian is finishing a meal at his favorite restaurant. The check shows that the cost of the food is $42. He adds a 15% tip to the

Rus_ich [418]

Answer:

48.30

Step-by-step explanation:

First determine the tip

42 *15%

42 *.15 =6.30

Add this to the amount of the tip

42 + 6.30 =48.30

The total amount is 48.30

7 0

3 years ago

The graph below shows the number of open blossoms in a nursery and the number of hours after dawn. answer all that apply

uysha [10]

Answer:

The correct option is B.

Step-by-step explanation:

The given equation is

$y=20x+3$

This equation represent the number of open blossoms in a nursery after x hours.

At initial the number hours is 0.

Substitute x=0 in the given equation.

$y=20(0)+3$

$y=0+3$

$y=3$

The initial value is 3, it means there were three blossoms open at dawn. Option B is correct.

6 0

3 years ago

Polygon ABCD is plotted on a coordinate plane and then rotated 90° clockwise about point C to form polygon A′B′C′D′. Match each

horrorfan [7]

The vertices of ABCD after 90 degrees clockwise rotation about point C are: A' (0,6), B' (3,7), C' (4,6) and D' (4,3)

<h3>How to match the vertices of the polygon?</h3>

The image of the polygon ABCD is not given; however, the question can still be answered because the coordinates are known.

The vertices of polygon ABCD are given as:

A = (4, 6)

B = (5, 3)

C = (4, 2)

D = (1, 2)

The rule of rotation about point C is:

(x,y) = (a + b - y, x + b - a)

Where:

(a, b) = (4, 2) --- the point of rotation.

So, we have:

(x,y) = (4 + 2 - y, x + 4 - 2)

(x,y) = (6 - y, x + 2)

The above means that:

A' = (6 - 6, 4 + 2) = (0,6)

B' = (6 - 3, 5 + 2) = (3,7)

C' = (6 - 2, 4 + 2) = (4,6)

D' = (6 - 2, 1 + 2) = (4,3)

Hence, the image of the rotation and their vertices (i.e. coordinates) are:

A' = (0,6)

B' = (3,7)

C' = (4,6)

D' = (4,3)