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Debora [2.8K]
3 years ago
7

Solve the equation. x2 = 160

Mathematics
2 answers:
UNO [17]3 years ago
8 0
          <span> x = 4 • ± √10 = ± 12.6491

</span>
zhannawk [14.2K]3 years ago
7 0
80 because 160 divided by 2 is 80 so 2 x 80
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Find the area of each shape. Show your reasoning.
Troyanec [42]

Answer:

Those areas are: A 1 = 12,  A 2 = 19

Step-by-step explanation:

The area of shape 1  : it consists of 1 square + 4 right triangles

Area of the square: A = a², area of the triangle: A = 1/2 · a · h

A 1 = 2² + 4 · 1/2 · 2 · 2 = 4 + 8 = 12

The area of shape 2 :  it consists of 2  isosceles triangles

A 2 = 1/2 · 2 · 4 + 1/2 · 6 · 5 = 4 + 15 = 19

3 0
3 years ago
Which of these functions had a greater rate of change than the function graphed below, and why?
Mrac [35]

Answer:

C

Step-by-step explanation:

When we talk of rate of change, we talk of the slope of the line

If we had a line;

y = mx + b

m is the slope ( which is the rate of change)

To get the slope of the line, we select any two points on the line and apply the slope formula

m = y2-y1/x2-x1

let us take points (0,0) and (3,9)

m = 9-0/3-0 = 9/3 = 3

The slope here is 3

so from the option, we can see that the third option is the correct answer

7 0
3 years ago
A right circular cylinder has a volume of 500 cu in. If the base has a radius of 4 in., what's the altitude of the cylinder? Rou
GarryVolchara [31]
<span>Cylinder Volume   =   </span><span>π <span>• r² • height
height = </span></span><span>Cylinder Volume / (PI * radius^2)
</span><span>height = 500 cubic inches / 3.14159 * 16
</span><span><span><span>height = 9.9471839432 </span> </span> </span>
<span>height = 9.95 (rounded)

</span>


4 0
3 years ago
Graph a triangle (STU) and reflect it over the y-axis to create triangle ST'U'.
lukranit [14]

The x-coordinates of \triangle S'T'U' will be the negation of the x-coordinates of \triangle STU

The line segment from S to the y-axis equals the line segment from S' to the y-axis. Similarly, the line segment from T to the y-axis equals the line segment from T' to the y-axis

See attachment for \triangle STU and \triangle S'T'U'

In order to solve this question, I will make the following assumptions.

Assume that the coordinates of \triangle STU are

S = (4,5)      

T = (5,9)

U=(3,8)

Refer to attachment for illustrations

<u>(1) Reflect </u>\triangle STU<u> over y-axis and describe the transformation</u>

To reflect \triangle STU across the y-axis, the following rule must be followed

(x,y) \to (-x,y)

This means that:

S = (4,5) \to S' = (-4,5)

T = (5,9) \to T' = (-5,9)

U=(3,8) \to U'=(-3,8)

<u>The description of the </u><u>transformation </u><u>is as follows:</u>

Notice that the signs of the x-coordinates \triangle STU and \triangle S'T'U' of both triangles are different.

In other words, if the x-coordinate of one is positive, then the other will have a negative x-coordinate; and vice versa.

<u>(2) Compare the segments and the line of reflection</u>

To reflect across the y-axis means that the reflecting line is the y-axis, itself.

The distance between a point to the y-axis is the absolute value of the x-coordinate.

So, the distance between S and the y-axis is:

S = |4| = 4

The distance between S' and the y-axis is:

S' = |-4| = 4

We can conclude that the two line segments are equal.

This is the same for other point T and T' because of the formula used above.

<u>From T and T' to the y-axis is:</u>

T =|5| =5

T' =|-5| =5

Read more at:

brainly.com/question/938117

8 0
3 years ago
8/3 +8/-7. What is answer
MArishka [77]

Answer:

1.52380952381 is the correct ans

8 0
3 years ago
Read 2 more answers
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