Solve the equation. x2 = 160
2 answers:
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Answer:
The scale factor is (√10) / (4)
Explanation:
The complete question as well as the rule for the distance between two points are shown in the attached image.
To get the scale factor, we will follow these steps:
1- Length of AB:
AB = √(5-9)²+(-4-4)²
AB = √80
AB = 4√5 units
2- Length of A'B':
A'B' = √(5-6)²+(-4-3)²
A'B' = √50
A'B' = 5√2
3- getting the scale factor:
A'B' = k AB where k is the scale factor
5√2 = k * 4√5
k = (√10) / (4)
Hope this helps :)
The scale factor is (√10) / (4)
Explanation:
The complete question as well as the rule for the distance between two points are shown in the attached image.
To get the scale factor, we will follow these steps:
1- Length of AB:
AB = √(5-9)²+(-4-4)²
AB = √80
AB = 4√5 units
2- Length of A'B':
A'B' = √(5-6)²+(-4-3)²
A'B' = √50
A'B' = 5√2
3- getting the scale factor:
A'B' = k AB where k is the scale factor
5√2 = k * 4√5
k = (√10) / (4)
Hope this helps :)