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Rus_ich [418]
1 year ago
8

If the surface area of a sphere is 22176 sq.cm than find it's radius.​

Mathematics
2 answers:
mr_godi [17]1 year ago
7 0

Answer:

3,531

Step-by-step explanation:

22,176 cm2 ÷ pie 3.14 = 7062

7062 ÷ 2 = 3531 radius

kondor19780726 [428]1 year ago
4 0

the surface area of a sphere: 4πr²

22176 = 4πr²

r² = 22176/4π

r = 42 cm

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Help solve for surface area btw
spayn [35]
SA=2lw+2lh+2hw ..........
7 0
2 years ago
Write each quotient as a fraction or mixed number.<br><br>SHOW WORK
12345 [234]

Answer:

4 ÷ 5 = 2/5

5 ÷ 4 = 1 1/4

12 ÷ 30 = 2/5

30 ÷ 12 = 2 1/2

6 0
2 years ago
What 1 thruogh 100 added up them divided
Marina CMI [18]
We can use the sum of an aritmetic sequence
the sum from n=1 to n=r when the first term is a1 and the nth term is an is
S=\frac{n(a_1+a_n)}{2}
first term is 1
last term is 100
there are 100 terms so n=100

so the sum is S=\frac{100(1+100)}{2}
S=(50)(101)
S=5050
now you want us to divide by 10
5050/10=505


fun fact, gauss (famous math guy) did this when he was younger, legend has it that he was assigned this as an in class assigment to kill time but gauss found a neat pattern, he noticed that adding the end terms wer giving the same sum, example, 100+1=101, 2+99=101, etc, so he just needed to find al the pairs and add them all up




answer is 505
the result is 505
5 0
2 years ago
State the domain restriction(s) in interval notation of \displaystyle f\left(g\left(x\right)\right)f(g(x)) given: \displaystyle
DENIUS [597]

Answer:

The interval notation for the domain is [\frac{23}{3},\infty  ].

Step-by-step explanation:

Consider the provided information.

It is given that \:f\left(x\right)=\sqrt{3x-2},\:\text{ and }\:g\left(x\right)=x-7

We need to find the value of f\left(g\left(x\right)\right).

Put the value of g(x) in  f\left(g\left(x\right)\right).

f\left(g\left(x\right)\right)=f(x-7)  ....(1)

Now, put x=x-7 in \:f\left(x\right)=\sqrt{3x-2}

\:f\left(x-7\right)= \sqrt{3(x-7)-2}

\:f\left(x-7\right)= \sqrt{3x-21-2}

\:f\left(x-7\right)= \sqrt{3x-23}

From equation 1.

f\left(g\left(x\right)\right)=\:f\left(x-7\right)= \sqrt{3x-23}

The domain of the function is the set of input values for which a function is defined.

Here, the value of 3x-23 should be greater or equal to 0 as the square root of a negative number is not real.

Domain= 3x-23\geq0

x\geq\frac{23}{3}

The value of x is all real number greater than \frac{23}{3}.

Hence, the interval notation for the domain is [\frac{23}{3},\infty  ].

7 0
2 years ago
Simplify (3+√5)(5+√3)
Scorpion4ik [409]

Answer:

answer of this question is

35.24

8 0
3 years ago
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