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KiRa [710]
3 years ago
9

The area, a, of a square whose side length is n

Mathematics
1 answer:
svetlana [45]3 years ago
3 0

Answer:

a*n=area

Step-by-step explanation:

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In JKL, k=4.1 cm,j=3.8 cm and angle J=Q3^ Find all possible values of angle K , to the nearest inch of a degree .
spayn [35]

Answer:

74.0°

Step-by-step explanation:

In triangle JKL, k = 4.1 cm, j = 3.8 cm and ∠J=63°. Find all possible values of angle K, to the  nearest 10th of a degree

Solution:

A triangle is a polygon with three sides and three angles. Types of triangles are right angled triangle, scalene triangle, equilateral triangle and isosceles triangle.

Given a triangle with angles A, B, C and the corresponding sides opposite to the angles as a, b, c. Sine rule states that for the triangle, the following holds:

\frac{a}{sin(A)}=\frac{b}{sin(B)}=\frac{c}{sin(C)}

In triangle JKL, k=4.1 cm, j=3.8 cm and angle J=63°.

Using sine rule, we can find ∠K:

\frac{k}{sin(K)}=\frac{j}{sin(J)}   \\\\\frac{4.1}{sin(K)}=\frac{3.8}{sin(63)}  \\\\sin(K)=\frac{4.1*sin(63)}{3.8}\\\\sin(K)=0.9613\\\\K=sin^{-1} (0.9613)\\\\K=74.0^o  \\

6 0
3 years ago
Differentiate y=xln(3x)​
Ganezh [65]

Answer:

Remove parentheses.

y=xln3x

2 Already solved. No work needed.

y=xln3x

the solution is in the picture above please mark me brainliest:)

6 0
3 years ago
Read 2 more answers
at the start of 2014 mikes car was worth 12000 thee value of the car decreased by 30% every year work out the value of his car a
Bas_tet [7]

Answer:

4116

Step-by-step explanation:

2014

12000÷10=1200 (10%)

1200x3=3600

12000-3600=8400

2015

8400÷10=840

840x3=2520

8400-2520=5880

2016

5880÷10=588

588x3=1764

5880-1764=4116

7 0
3 years ago
Find the length of diagonal XU in the hexagon below. Round your solution to 2 decimal points
SpyIntel [72]

Answer:

The length of diagonal XU is 6.40 units

Step-by-step explanation:

* Lets explain how to find the distance between two points

- The rule of the distance between two points (x_{1},y_{1})

 and (x_{2},y_{2}) is:

 d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

* Lets solve the problem

-From the attached figure:

- The coordinates of the vertex X are (2 , 2)

- The coordinates of the vertex U are (-2 , 7)

∴ The point (x_{1},y_{1}) = (2 , 2)

∴ The point (x_{2},y_{2}) = (-2 , 7)

∴ x_{1}=2,x_{2}=-2

∴  y_{1}=2,y_{2}=7

∵ d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

∴ d=\sqrt{(-2-2)^{2}+(7-2)^{2}}=\sqrt{(-4)^{2}+(5)^{2}}=\sqrt{16+25}=\sqrt{41}

∵ \sqrt{41}=6.403124

∴ d = 6.40

* The length of diagonal XU is 6.40 units

6 0
3 years ago
Directions: Identify the slope (m) and y-intercept (b) of the graph of each equation
loris [4]

Answer:

m = -4, b = -12

Step-by-step explanation:

m is slope and it is the coefficient of x

b is the y intercept

5 0
3 years ago
Read 2 more answers
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