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Lemur [1.5K]
3 years ago
5

25% of 56. We are practicing finding the percent of each number

Mathematics
2 answers:
Karo-lina-s [1.5K]3 years ago
8 0
25% is 1/4. Do 56 divided by 4, you get 14
Margarita [4]3 years ago
5 0
You would divide 56 by 4 to get 14. 25% of 56 =14.
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YP_2021_Math 8_Progress Monitor_02
Lisa [10]
(4,4).........................
7 0
3 years ago
A.) 170<br> B.) 300<br> C.)280<br> D.)155<br> Please help me
pav-90 [236]

Answer:

Step-by-step explanation:

The formula for this is

∠G = 1/2(arcEH - arcHF)

We have angle G (5x - 10) and we have arcEH (195) so we have to solve for x to find the measure of arcEHF so we can add arcEH + arcHF = arcEHF

Filling in the formula with what we have:

5x-10=\frac{1}{2}(195-(8x+17))

which simplifies down a bit to

5x-10=\frac{1}{2}(195-8x-17) which simplifies down a bit more to

5x-10=\frac{1}{2}(178-8x) Multiply both sides by 2 to get rid of the fraction and get:

2(5x - 10) = 178 - 8x which of course simplifies to

10x - 20 = 178 - 8x. Now add 8x to both sides and at the same time add 20 to both sides to get:

18x = 198 so

x = 11. Now we can find the measure of arcHF:

arcHF is 8x + 17, so arcHF is 8(11) + 17 which is 105°.

arcEH + arcHF = arcEHF so

195 + 105 = arcEHF so

arcEHF = 300°

6 0
3 years ago
PLZ HELP ASAP FOR BRAINLIEST
kykrilka [37]

Answer:

1/4

Step-by-step explanation:

You can set up ratios or fractions for the matching sides.

A/B

1/4 = 1/4

1.1/ 4/4= 1/4

1.5/6 = 1/4

5 0
3 years ago
Read 2 more answers
Which expression shows 12 more than the quotient of 63 and 9.
Black_prince [1.1K]
Hello!

The quotient means dividing

The quotient of 63 and 9 is 63/9

12 more means we add

The expression is 63/9 + 12 or 12 + 63/9

Hope this helps!
5 0
3 years ago
Read 2 more answers
Find the work done by force dield f(x,y)=x^2i+ye^xj on a particle that moves along parabola x=y^2+1 from(1,0) to (2,1)
NemiM [27]
Call the parabola P, parameterized by \mathbf r(y)=\langle y^2+1,y\rangle with 0\le y\le 1\rangle. Then the work done by \mathbf f(x,y) along P is

\displaystyle\int_P\mathbf f(x,y)\cdot\mathrm d\mathbf r=\int_{y=0}^{y=1}\mathbf f(x(y),y)\cdot\dfrac{\mathrm d\mathbf r(y)}{\mathrm dy}\,\mathrm dy
=\displaystyle\int_0^1\langle(y^2+1)^2,ye^{y^2+1}\rangle\cdot\langle2y,1\rangle\,\mathrm dy
=\displaystyle\int_0^1(2y^5+4y^3+2y+ye^{y^2+1})\,\mathrm dy=\frac73-\frac e2+\frac{e^2}2
8 0
3 years ago
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