All categories

3 years ago

Is (2,-2) a solution to the following system of equations?

Mathematics

2 answers:

SCORPION-xisa [38]3 years ago

8 0

Answer:

yes?

Step-by-step explanation:

is this a true or false question

(its true)

Nana76 [90]3 years ago

8 0

Answer:

Step-by-step explanation:

Remark

If it was, the value for x should give you the same y in both cases. Try it out.

<u>First Equation</u>

y = -2x + 2

x = 2

y = -2*2 + 2 = -4 + 2 = - 2

<u>Second equation</u>

x = 2

y = 7*2 + 11

y = 14 + 11

y = 25

Conclusion

They are no where near being the same

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Which of the following is the complete factorization of 10x - 3 - 3x2? -(3x + 1)(x - 3) -(3x - 1)(x - 3) (3x - 1)(x + 3)

qaws [65]

Answer:

$=-\left(3x-1\right)\left(x-3\right)$

Step-by-step explanation:

$10x-3-3x^2\\\mathrm{Factor\:out\:common\:term\:}-1\\=-\left(3x^2-10x+3\right)\\\mathrm{Factor}\:3x^2-10x+3:\quad \left(3x-1\right)\left(x-3\right)\\3x^2-10x+3\\\mathrm{Write\:in\:the\:standard\:form}\:ax^2+bx+c\\=3x^2-10x+3\\\mathrm{Break\:the\:expression\:into\:groups}\\=\left(3x^2-x\right)+\left(-9x+3\right)\\\mathrm{Factor\:out\:}x\mathrm{\:from\:}3x^2-x\mathrm{:\quad }x\left(3x-1\right)\\3x^2-x\\\mathrm{Apply\:exponent\:rule}:\quad \:a^{b+c}=a^ba^c\\x^2=xx\\=3xx-x$

$\mathrm{Factor\:out\:common\:term\:}x\\=x\left(3x-1\right)\\\mathrm{Factor\:out\:}-3\mathrm{\:from\:}-9x+3\mathrm{:\quad }-3\left(3x-1\right)\\-9x+3\\\mathrm{Rewrite\:}9\mathrm{\:as\:}3\cdot \:3\\=-3\cdot \:3x+3\\\mathrm{Factor\:out\:common\:term\:}-3\\=-3\left(3x-1\right)\\=x\left(3x-1\right)-3\left(3x-1\right)\\\mathrm{Factor\:out\:common\:term\:}3x-1\\=\left(3x-1\right)\left(x-3\right)\\=-\left(3x-1\right)\left(x-3\right)$

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Alex787 [66]

Answer:

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Step-by-step explanation:

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Umnica [9.8K]

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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