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3 years ago

Is (2,-2) a solution to the following system of equations?

Mathematics

2 answers:

SCORPION-xisa [38]3 years ago

8 0

Answer:

yes?

Step-by-step explanation:

is this a true or false question

(its true)

Nana76 [90]3 years ago

8 0

Answer:

Step-by-step explanation:

Remark

If it was, the value for x should give you the same y in both cases. Try it out.

First Equation

y = -2x + 2

x = 2

y = -2*2 + 2 = -4 + 2 = - 2

Second equation

x = 2

y = 7*2 + 11

y = 14 + 11

y = 25

Conclusion

They are no where near being the same

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3(2y + 3) = 1(y + 1)

777dan777 [17]

Answer:

= − 8/5

Step-by-step explanation:

Distribute

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5 0

3 years ago

Read 2 more answers

According to the graph, what is the value of the constant in the equation below

Dmitry [639]

Step-by-step explanation:

There is no graph .so there is no way it can be answered.

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3 years ago

Which sum will be neither positive nor negative. a. 3+2 b. -4+(-4) c. -6+6 d. 7+(-6)

anastassius [24]

Answer:

Step-by-step explanation:

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3 years ago

Find the square roots of the two factors of √36 and multiply them.

PolarNik [594]

Answer:

The square root is 6.

Step-by-step explanation:

4 0

3 years ago

Look at the picture

Sonbull [250]

$\large\displaystyle\text{$\begin{gathered}\sf 9|x-8| < 36 \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf Divide \ both \ sides \ by \ 9. \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf \frac{9(|x-8|)}{9} < \frac{36}{9} \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf |x-8| < 4 \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf Solve \ Absolute \ Value. \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf |x-8| < 4 \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf We \ know \ x-8 < 4 \ and \ x-8 > -4 \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf x-8 < 4 \ (Condition \ 1) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x-8+8 < 4+8 \ (Add \ 8 \ to \ both \ sides) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x < 12 \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf x-8 > -4 \ (Condition \ 2) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x-8+8 > -4+8 \ (Add \ 8 \ to \ both \ \ sides) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x > 4 \end{gathered}$}$

$\underline{\boldsymbol{\sf{Answer}}}$

$\boxed{\large\displaystyle\text{$\begin{gathered}\sf x < 12 \ and \ x > 4 \end{gathered}$} }$

$\large\displaystyle\text{$\begin{gathered}\sf Therefore,\bf{\underline{the \ correct \ option}} \ \end{gathered}$}\large\displaystyle\text{$\begin{gathered}\sf is \ \bf{\underline{"A"}}. \end{gathered}$}$

6 0

2 years ago