For proof of 3 divisibility, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.
<h3>
Integers divisible by 3</h3>
The proof for divisibility of 3 implies that an integer is divisible by 3 if the sum of the digits is a multiple of 3.
<h3>Proof for the divisibility</h3>
111 = 1 + 1 + 1 = 3 (the sum is multiple of 3 = 3 x 1) (111/3 = 37)
222 = 2 + 2 + 2 = 6 (the sum is multiple of 3 = 3 x 2) (222/3 = 74)
213 = 2 + 1 + 3 = 6 ( (the sum is multiple of 3 = 3 x 2) (213/3 = 71)
27 = 2 + 7 = 9 (the sum is multiple of 3 = 3 x 3) (27/3 = 9)
Thus, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.
Learn more about divisibility here: brainly.com/question/9462805
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Answer:
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Step-by-step explanation:
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The solution is at what point the two lines intersect.
Plug y into the other equation to get: 5x-4(5-3x)=-3
Multiply it out: 5x+12x-20=-3
Combine like terms and add 20 to both sides: 17x=17
Divide both sides by 17: x=1
Now plug the x value back into any equation to get the y value.
So you get y=5-3(1) --> y=2
The solution is (1, 2)
This can be solved using trigonometric functions. The distance x serves as one leg of a triangle, and makes an angle q with the hypotenuse. The distance from the tip of the rocket to the ground make up the other leg of the triangle. So solving this:
tan q = y / x
Where: y = distance from the tip of the rocket to the ground
Therefore, y = x tan q
Among the choices, the correct answer is C.