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3 years ago

Nth term of this sequence 1, 10, 19, 28

Mathematics

1 answer:

mestny [16]3 years ago

3 0

Answer:

The nth term of the sequence is

Step-by-step explanation:

The sequence above is an arithmetic sequence

For an nth term in an arithmetic sequence

A(n) = a + ( n - 1)d

where a is the first term

n is the number of terms

d is the common difference

From the question

a = 1

d = 10 - 1 = 9 or 19 - 10 = 9 or 28 - 19 = 9

So the nth term of the sequence is

A(n) = 1 + (n - 1)9

= 1 + 9n - 9

= 9n - 8

Hope this helps you

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ladessa [460]

Given:

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To find:

The value of r.

Solution:

We have,

$AB=6\ BC=r,\ CD=r,\ AD=12$ .

We know that the radius is perpendicular to the tangent at the point of tangency

AD is the tangent and CD is the radius. So, CD is perpendicular to AD at point D, i.e., $m\angle D=90^\circ$ .

Using Pythagoras theorem, we get

$AC^2=AD^2+CD^2$

$(6+r)^2=12^2+r^2$

$36+12r+r^2=144+r^2$

$12r=144+r^2-36-r^2$

On further simplification, we get

$12r=108$

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Therefore, the value of r is 9.

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2 years ago

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PSYCHO15rus [73]

Let;

A(-8,6) B(6,6) C(6, -4) D(-8, -4)

Let's find the length AB

x₁= -8 y₁=6 x₂=6 y₂=6

We will use the distance formula;

$d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}$

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Next, we will find the width BC

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1 year ago