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Maurinko [17]
3 years ago
8

Please help ASAP I will mark brainlest

Mathematics
1 answer:
morpeh [17]3 years ago
3 0

Answer:

Answer C is the only one in function notation.

Step-by-step explanation:

To find something in function notation, we look for 2 different criteria.

  • On the left side, it must say f( ), with a variable in the parenthesis.
  • On the right side, the variable being used must match that from the left side.

Since C is the only one that satisfies both of those needs, we know it is the answer.

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Consider the line segment YZ with endpoints Y(-3,-6) and Z(7,4). What is the y-coordinate of the midpoint of line segment YZ?
tatiyna

Given:

Consider the line segment YZ with endpoints Y(-3,-6) and Z(7,4).

To find:

The y-coordinate of the midpoint of line segment YZ.

Solution:

Midpoint formula:

Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

The endpoints of the line segment YZ are Y(-3,-6) and Z(7,4). So, the midpoint of YZ is:

Midpoint=\left(\dfrac{-3+7}{2},\dfrac{-6+4}{2}\right)

Midpoint=\left(\dfrac{4}{2},\dfrac{-2}{2}\right)

Midpoint=\left(2,-1\right)

Therefore, the y-coordinate of the midpoint of line segment YZ is -1.

8 0
3 years ago
find the slope and the y-intercept of the graph of the linear equation.y=−3−14xy=−3−14xthe slope isand the y-intercept is.
Vladimir79 [104]

Answer:

add the graph

Step-by-step explanation:

6 0
3 years ago
Write the polynomial in standard form. Then name the polynomial based on its degree and number of terms.
gavmur [86]
To answer the question, simplify the polynomial by adding those that has the same degree of variable,
                                   6 - 3x + (6x³ - 2x³)
                                   6 - 3x + 4x³
Rearrange the polynomial with decreasing exponent or x,
                                     4x³ - 3x + 6
This is a third-degree polynomial. 
5 0
3 years ago
Read 2 more answers
Geometric Sequence S = 1.0011892 + ... + 1.0012 + 1.001 + 1
leva [86]

Answer:

<em />S_{1893} =5632.98<em />

<em />

Step-by-step explanation:

The correct form of the question is:

S = 1.001^{1892} + ... + 1.001^2 + 1.001 + 1

Required

Solve for Sum of the sequence

The above sequence represents sum of Geometric Sequence and will be solved using:

S_n = \frac{a(1 - r^n)}{1 - r}

But first, we need to get the number of terms in the sequence using:

T_n = ar^{n-1}

Where

a = First\ Term

a = 1.001^{1892}

r = common\ ratio

r = \frac{1}{1.001}

T_n = Last\ Term

T_n = 1

So, we have:

T_n = ar^{n-1}

1 = 1.001^{1892} * (\frac{1}{1.001})^{n-1}

Apply law of indices:

1 = 1.001^{1892} * (1.001^{-1})^{n-1}

1 = 1.001^{1892} * (1.001)^{-n+1}

Apply law of indices:

1 = 1.001^{1892-n+1}

1 = 1.001^{1892+1-n}

1 = 1.001^{1893-n}

Represent 1 as 1.001^0

1.001^0 = 1.001^{1893-n}

They have the same base:

So, we have

0 = 1893-n

Solve for n

n = 1893

So, there are 1893 terms in the sequence given.

Solving further:

S_n = \frac{a(1 - r^n)}{1 - r}

Where

a = 1.001^{1892}

r = \frac{1}{1.001}

n = 1893

So, we have:

S_{1893} =\frac{1.001^{1892} *(1 -\frac{1}{1.001}^{1893})}{1 -\frac{1}{1.001} }

S_{1893} =\frac{1.001^{1892} *(1 -\frac{1}{1.001}^{1893})}{\frac{1.001 -1}{1.001} }

S_{1893} =\frac{1.001^{1892} *(1 -\frac{1}{1.001}^{1893})}{\frac{0.001}{1.001} }

S_{1893} =\frac{1.001^{1892} *(1 -\frac{1}{1.001^{1893}})}{\frac{0.001}{1.001} }

Simplify the numerator

S_{1893} =\frac{1.001^{1892}  -\frac{1.001^{1892}}{1.001^{1893}}}{\frac{0.001}{1.001} }

S_{1893} =\frac{1.001^{1892}  -1.001^{1892-1893}}{\frac{0.001}{1.001} }

S_{1893} =\frac{1.001^{1892}  -1.001^{-1}}{\frac{0.001}{1.001} }

S_{1893} =(1.001^{1892}  -1.001^{-1})/({\frac{0.001}{1.001} })

S_{1893} =(1.001^{1892}  -1.001^{-1})*{\frac{1.001}{0.001}}

S_{1893} =\frac{(1.001^{1892}  -1.001^{-1}) * 1.001}{0.001}

Open Bracket

S_{1893} =\frac{1.001^{1892}* 1.001  -1.001^{-1}* 1.001 }{0.001}

S_{1893} =\frac{1.001^{1892+1}  -1.001^{-1+1}}{0.001}

S_{1893} =\frac{1.001^{1893}  -1.001^{0}}{0.001}

S_{1893} =\frac{1.001^{1893}  -1}{0.001}

S_{1893} =5632.97970294

Hence, the sum of the sequence is:

<em />S_{1893} =5632.98<em> ----- approximated</em>

4 0
3 years ago
Rounding 2.289 to the nearest tenth
Lostsunrise [7]

rounding 2.289 to the nearest ten gives you 0. its that simple ;)

8 0
3 years ago
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